pynative

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Python Basic Exercise for Beginners

Filed Under: Python Exercises | 17 Comments

This Python essential exercise is to help Python beginners to learn necessary Python skills quickly. Practice Python Basic Concepts such as Loops, Control structure, List, Strings, input-output, and built-in functions.

What Questions included in this Python fundamental exercises?

  • Exercise contains 10 questions. The solution provided for each question.
  • Each question contains a specific skill you need to learn.

Practice Questions using Code Editor

I have added tips and required learning resources for each question, which help you to solve the exercise. When you complete each question, you get more familiar with a control structure, loops, string, and list in Python.

Question 1: Accept two int values from user and return their product. If the product is greater than 1000, then return their sum

Reference article for help:

def multiplication_or_sum(num1, num2):
  product = num1 *num2
  if(product < 1000):
    return product
  else:
    return num1 +num2

number1 = int(input("Enter first number "))
number2 = int(input("Enter second number"))

result = multiplication_or_sum(number1, number2)
print("The result is", result)

Output:

Enter first number 10
Enter second number 20
The result is 200

Question 2: Given a range of numbers. Iterate from o^th number to the end number and print the sum of the current number and previous number

Reference article for help:

def sumNum(num):
  previousNum=0
  for i in range(num):
    sum = previousNum + i
    print(sum)
    previousNum = i

print("Printing current and previous number sum in a given range")
sumNum(10)

Output:

Printing current and previous number sum in a given range
0
1
3
5
7
9
11
13
15
17

Question 3: Accept string from the user and display only those characters which are present at an even index

For example str = "pynative" so you should display ‘p’, ‘n’, ‘t’, ‘v’.

Reference article for help:

def printEveIndexChar(str):
  for i in range(0, len(str)-1, 2):
    print("index[",i,"]", str[i] )

inputStr = input("Enter String ")
print("Orginal String is ", inputStr)

print("Printing only even index chars")
printEveIndexChar(inputStr)

Output:

Enter String  pynative
Orginal String is  pynative
Printing only even index chars
index[ 0 ] p
index[ 2 ] n
index[ 4 ] t
index[ 6 ] v

Question 4: Given a string and an int n, remove characters from string starting from zero upto n and return a new string

Note: n must be less than length of string. For example, removeChars("pynative", 4) so output must be “tive”.

def removeChars(str, n):
  return str[n:]

print("Removing n number of chars")
print(removeChars("pynative", 4))

Output:

Removing n number of chars
tive

Question 5: Given a list of ints, return True if first and last number of a list is same

def isFirst_And_Last_Same(numberList):
  firstElement = numberList[0]
  lastElement =  numberList[-1]
  if(firstElement == lastElement):
    return True
  else:
    return False

numList = [10, 20, 30, 40, 10]

print("The first and last number of a list is same")
print("result is", isFirst_And_Last_Same(numList))

Output:

the first and last number of a list is same
result is True

Question 6: Given a list of numbers, Iterate it and print only those numbers which are divisible of 5

def findDivisible(numberList):
  for num in numberList:
    if (num % 5 == 0):
      print(num)

numList = [10, 20, 33, 46, 55]
print("Finding divisible of 5 in a list")
findDivisible(numList)

Output:

Finding divisible of 5
10
20
55

Question 7: Return the number of times that the string “Emma” appears anywhere in the given string

Given string is “Emma is a good developer. Emma is also a writer” and output should be 2.

Reference article for help: Python range() function

def count_jhon(statement):
  count = 0
  for i in range(len(statement)-1):
    count += statement[i:i+4] == 'Emma'
  return count

count = count_jhon("Emma is good developer. Emma is aslo a writer")
print("Emma appeared ", count, "times")

Output:

Emma appeared  2 times

Question 8: Print the following pattern

1 
2 2 
3 3 3 
4 4 4 4 
5 5 5 5 5

Reference article for help: Print Pattern using for loop

for num in range(10):
    for i in range(num):
        print (num, end=" ") #print number
    # new line after each row to display pattern correctly
    print("\n")

Question 9: Reverse a given number and return true if it is the same as the original number

def reverseCheck(number):
  originalNum = number
  reverseNum=0
  while(number > 0):
    reminder = number % 10
    reverseNum  = (reverseNum *10) + reminder
    number = number // 10
  if(originalNum  == reverseNum):
    return True
  else:
    return False
    
print("orignal and revers number is equal")
print(reverseCheck(121))

Output:

Orignal and revers number is equal
True

Question 10: Given a two list of ints create a third list such that should contain only odd numbers from the first list and even numbers from the second list

def mergeList(listOne, listTwo):
  thirdList = []
  for num in listOne:
    if(num % 2 != 0):
      thirdList.append(num)
  for num in listTwo:
    if(num % 2 == 0):
      thirdList.append(num)
  return thirdList
    
print("Merged List is")
listOne = [10, 20, 23, 11, 17]
listTwo = [13, 43, 24, 36, 12]

print(mergeList(listOne, listTwo))

Output:

Merged List is
[23, 11, 17, 24, 36, 12]

Let me know your suggestions and feedback in the comment section below.

 

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Comments

  1. Dear Vishal,
    I tried Question 1 and failed as compare to your solution. I think your question was wrongly phrased.
    My solution is
    #It is assumed user will enter integers only, no check on input
    first = int(input(“Enter first integer “))
    second = int(input(“Enter second integer “))

    product = first * second
    print (“Product is “, product)

    if product > 1000:
    print(“Sum as product > 1000 : “, first + second)

    Your Question should have been
    Question 1: Accept two integer values from user.
    Calculate their product and if the product is greater than 1000
    then return their sum otherwise return their product.

    Regards,
    Joseph

    Reply

  2. May I suggest a more concise solution to question no. 9?

    orignum= 234565432
    revnum=(str(orignum)[::-1])
    print(revnum)
    if str(orignum) == revnum:
    print(‘True: The number is the same when reversed’)

    Reply

  3. user_input = input(“input any string”)
    for a, j in enumerate(range(0, len(user_input), 2)):
    print(user_name)
    # means square bracket

    Reply

  4. Vishal I think your solution to question1 is a little verbose, a straight if and else statement does the job just well, it Will be much easier for beginners. I.e
    if product>1000:
    print(‘sum is: ‘, sum)
    else:
    print(‘product is: ‘, product)

    Reply

  5. Hi Vishal
    I think to help the beginners better, you should solve the problems without always using user defined functions, just Incase those that are not familiar with it.
    Don’t mind my frequent responses, am in love with PYTHON that’s why.
    Thanks

    Reply

  6. May I suggest an alternative solution to Q7.
    txt = ‘Emma is a good developer. Emma is also a writer.’
    count = 0
    lst = txt.split()
    for word in lst:
    if word == ‘Emma’:
    count += 1
    print(f’Emma appears {count} times in the string.’)

    Reply

  7. My alternative solution to Q10:
    list1 = [1, 2, 3, 4, 5, 6, 7, 8, 9]
    list2 = [21, 22, 23, 24, 25, 26]
    list1_odd = [e for e in list1 if e%2 != 0]
    list2_even = [e for e in list2 if e%2 == 0]
    list3 = []
    list3.extend(list1_odd)
    list3.extend(list2_even)
    print(list1)
    print(list2)
    print(list3)

    Reply

  8. Just a general comment on these Comment boxes. Like me, I suspect most respondents post the python code by pasting from an editor (such as the Trinket one provided here). Unfortunately the mark-up behind this Comment box does not appear to support tab characters, so the all-important pythonic indentation is lost. This could be very confusing for a beginner, particularly where multi-line code blocks are concerned. Any way you could rectify this please?

    (In the meanwhile, the workaround would appear to be to manually replace any tabs with 4 spaces, but that is prone to editing error or omissions.)

    Reply

  9. Hello Vishal.

    I really am grateful for the work you put in to make this resource. This comment is a token of my thanks. I am a beginner programmer and this is helping me increase my knowledge of Python.

    Cheers.

    Reply

  10. On exercise 3
    for i in range(0, len(str)-1, 2):
    I did not use -1 as a second parameter of range() because if I use it it doesnt show the last letter of the string.
    I did :
    for i in range(0,len(str),2):
    Am I Wrong?

    Reply

  11. There is a short way to attend the question 9.
    # Reverse a given number and return true if it is the same as the original number
    original_number = input(“Enter the number: “)
    reverse_number = original_number[::-1]
    if int(original_number) == int(reverse_number):
    print(“The reversed number is the same as the original one.”)
    else:
    print(“They are not the same.”)

    Reply

  12. Here’s a shorter solution for question 3 🙂 It uses slicing with a step of 2.

    >>> str = “pynative”
    >>> “”.join(str[::2])
    ‘pntv’

    Reply

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