Python Basic Exercise for Beginners

Last updated on July 21, 2020

This Python essential exercise is to help Python beginners to learn necessary Python skills quickly. Practice Python Basic Concepts such as Loops, Control structure, List, Strings, input-output, and built-in functions.

Further Reading: Explore All Python Exercises and Python Quizzes to practice Python.

What Questions included in this Python fundamental exercises?

The exercise contains 15 questions. The solution provided for each question.
Each question contains the basic skills you need to learn.

I have added tips and required learning resources for each question, which helps you to solve the exercise. When you complete each question, you get more familiar with a control structure, loops, string, and list in Python.

Use Online Code Editor to solve exercise questions.

Also, try to solve the basic Python Quiz for beginners

Question 1: Given a two integer numbers return their product and if the product is greater than 1000, then return their sum

Reference article for help:

Given:

number1 = 20
number2 = 30

Expected Output:

The result is 600

Given:

number1 = 40
number2 = 30

Expected Output:

The result is 70

Solution:

def multiplication_or_sum(num1, num2):
    product = num1 * num2
    if product <= 1000:
        return product
    else:
        return num1 + num2

number1 = 20
number2 = 30

print("\n")
result = multiplication_or_sum(number1, number2)
print("The result is", result)

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Question 2: Given a range of first 10 numbers, Iterate from start number to the end number and print the sum of the current number and previous number

Reference article for help:

Expected Output:

Printing current and previous number sum in a given range(10)
Current Number 0 Previous Number  0  Sum:  0
Current Number 1 Previous Number  0  Sum:  1
Current Number 2 Previous Number  1  Sum:  3
Current Number 3 Previous Number  2  Sum:  5
Current Number 4 Previous Number  3  Sum:  7
Current Number 5 Previous Number  4  Sum:  9
Current Number 6 Previous Number  5  Sum:  11
Current Number 7 Previous Number  6  Sum:  13
Current Number 8 Previous Number  7  Sum:  15
Current Number 9 Previous Number  8  Sum:  17

Solution:

def sumNum(num):
    previousNum = 0
    for i in range(num):
        sum = previousNum + i
        print("Current Number", i, "Previous Number ", previousNum," Sum: ", sum)
        previousNum = i

print("Printing current and previous number sum in a given range(10)")
sumNum(10)

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Question 3: Given a string, display only those characters which are present at an even index number.

For example str = "pynative" so you should display ‘p’, ‘n’, ‘t’, ‘v’.

Reference article for help: Python Input and Output

Expected Output:

Orginal String is  pynative
Printing only even index chars
p
n
t
v

Solution:

def printEveIndexChar(str):
  for i in range(0, len(str)-1, 2):
    print("index[",i,"]", str[i] )

inputStr = "pynative" 
print("Orginal String is ", inputStr)

print("Printing only even index chars")
printEveIndexChar(inputStr)

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Question 4: Given a string and an integer number n, remove characters from a string starting from zero up to n and return a new string

For example, removeChars("pynative", 4) so output must be tive. Note: n must be less than the length of the string.

Solution:

def removeChars(str, n):
  return str[n:]

print("Removing n number of chars")
print(removeChars("pynative", 4))

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Also try to solve Python String Exercise

Question 5: Given a list of numbers, return True if first and last number of a list is same

Expected Output:

Given list is  [10, 20, 30, 40, 10]
result is True
Given list is  [10, 20, 30, 40, 50]
result is False

Solution:

def isFirst_And_Last_Same(numberList):
    print("Given list is ", numberList)
    firstElement = numberList[0]
    lastElement = numberList[-1]
    if (firstElement == lastElement):
        return True
    else:
        return False

numList = [10, 20, 30, 40, 10]
print("result is", isFirst_And_Last_Same(numList))

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Question 6: Given a list of numbers, Iterate it and print only those numbers which are divisible of 5

Expected Output:

Given list is  [10, 20, 33, 46, 55]
Divisible of 5 in a list
10
20
55

Solution:

def findDivisible(numberList):
    print("Given list is ", numberList)
    print("Divisible of 5 in a list")
    for num in numberList:
        if (num % 5 == 0):
            print(num)

numList = [10, 20, 33, 46, 55]
findDivisible(numList)

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Also try to solve Python list Exercise

Question 7: Return the total count of sub-string “Emma” appears in the given string

Given string is “Emma is good developer. Emma is a writer”

Expected Output:

Emma appeared 2 times

Solution 1: Using string function count()

sampleStr = "Emma is good developer. Emma is a writer"
cnt = sampleStr.count("Emma")
print(cnt)

Solution 2: Without using any string function

def count_emma(statement):
    print("Given String: ", statement)
    count = 0
    for i in range(len(statement) - 1):
        count += statement[i: i + 4] == 'Emma'
    return count

count = count_emma("Emma is good developer. Emma is a writer")
print("Emma appeared ", count, "times")

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Question 8: Print the following pattern

Reference article for help: Print Pattern using for loop

Solution:

for num in range(10):
    for i in range(num):
        print (num, end=" ") #print number
    # new line after each row to display pattern correctly
    print("\n")

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Question 9: Reverse a given number and return true if it is the same as the original number

Expected Output:

original number 121
The original and reverse number is the same

original number 125
The original and reverse number is not same

Solution:

def reverseCheck(number):
    print("original number", number)
    originalNum = number
    reverseNum = 0
    while (number > 0):
        reminder = number % 10
        reverseNum = (reverseNum * 10) + reminder
        number = number // 10
    if (originalNum == reverseNum):
        return True
    else:
        return False

print("The original and reverse number is the same:", reverseCheck(121))

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Question 10: Given a two list of numbers create a new list such that new list should contain only odd numbers from the first list and even numbers from the second list

Expected Output:

First List  [10, 20, 23, 11, 17]
Second List  [13, 43, 24, 36, 12]

result List is [23, 11, 17, 24, 36, 12]

Solution:

def mergeList(listOne, listTwo):
    print("First List ", listOne)
    print("Second List ", listTwo)
    thirdList = []
    
    for num in listOne:
        if (num % 2 != 0):
            thirdList.append(num)
    for num in listTwo:
        if (num % 2 == 0):
            thirdList.append(num)
    return thirdList

listOne = [10, 20, 23, 11, 17]
listTwo = [13, 43, 24, 36, 12]

print("result List is", mergeList(listOne, listTwo))

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Note: Try to solve Python list Exercise

Also, Test you basic concepts using Basic Python Quiz for Beginners.

Question 11: Write a code to extract each digit from an integer, in the reverse order

Expected Output:

For example, if the given int is 7536, the output shall be “6 3 5 7“, with a space separating the digits.

Solution:

number = 7536
print("Given number", number)
while (number > 0):
    # get the last digit
    digit = number % 10
    
    # remove the last digit and repeat the loop
    number = number // 10
    print(digit, end=" ")

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Question 12: Calculate income tax for the given income by adhering to the below rules

Taxable Income	Rate (%)
First $10,000	0
Next $10,000	10
The remaining	20

Expected Output:

For example, suppose that the taxable income is $45000 the income tax payable is

$10000*0% + $10000*10% + $25000*20% = $6000.

Solution:

income = 45000
taxPayable = 0
print("Given income", income)

if income <= 10000:
    taxPayable = 0
elif income <= 20000:
    taxPayable = (income - 10000) * 10 / 100
else:
    # first 10,000
    taxPayable = 0

    # next 10,000
    taxPayable = 10000 * 10 / 100

    # remaining
    taxPayable += (income - 20000) * 20 / 100

print("Total tax to pay is", taxPayable)

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Question 13: Print multiplication table form 1 to 10

Expected Output:

1  2 3 4 5 6 7 8 9 10 		
2  4 6 8 10 12 14 16 18 20 		
3  6 9 12 15 18 21 24 27 30 		
4  8 12 16 20 24 28 32 36 40 		
5  10 15 20 25 30 35 40 45 50 		
6  12 18 24 30 36 42 48 54 60 		
7  14 21 28 35 42 49 56 63 70 		
8  16 24 32 40 48 56 64 72 80 		
9  18 27 36 45 54 63 72 81 90 		
10 20 30 40 50 60 70 80 90 100

Solution:

for i in range(1, 11):
    for j in range(1, 11):
        print(i * j, end=" ")
    print("\t\t")

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Question 14: Print downward Half-Pyramid Pattern with Star (asterisk)

* * * * *  
* * * *  
* * *  
* *  
*

Reference article for help: Print Pattern using for loop

Solution:

for i in range(6, 0, -1):
    for j in range(0, i - 1):
        print("*", end=' ')
    print(" ")

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Question 15: Write a function called `exponent(base, exp)` that returns an int value of base raises to the power of exp.

Note here exp is a non-negative integer, and the base is an integer.

Expected Output:

Case 1:

base = 2
exponent = 5

2 raises to the power of 5 is: 32 i.e. (2 *2 * 2 *2 *2 = 32)

Case 2:

base = 5
exponent = 4

5 raises to the power of 4 is: 625 i.e. (5 *5 * 5 *5 = 625)

Solution:

def exponent(base, exp):
    num = exp
    result = 1
    while num > 0:
        result = result * base
        num = num - 1
    print(base, "raises to the power of", exp, "is: ", result)

exponent(5, 4)

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So What Do You Think?

I want to hear from you. What do you think of this basic exercise? If you have better alternative answers to the above questions, please help others by commenting on this exercise.

I have shown only 15 questions in this exercise because we have Free topic-specific exercises to cover each topic practice in detail. Please have a look at it.

Comments

yahia mahmoud says

January 12, 2021 at 12:39 am
The most helpful site ever learned a lot, thanks.
———————–
```
The_most_helpful_site_ever = int(len(input("insert every word in pynative.com ")))
for i in range ( The_most_helpful_site_ever) :
    print("thanks ", end = "")
```
Reply
- Vishal says
  
  January 12, 2021 at 8:37 am
  
  Thank you, Yahia. I am glad you liked it.
  
  Reply
Amrita Mehta says

December 27, 2020 at 5:01 pm
Question 5
```
l = [10, 20, 30, 40, 10]
if l[0] == l[-1]:
    print("True")
else:
    print('False')
```
Reply
Amrita Mehta says

December 27, 2020 at 4:45 pm
Question 1
```
def calc(n1,n2):
    product = n1 * n2
    
    if product > 1000:
        return n1 + n2
    else:
        return product
    
print(calc(3000,2))
```
Reply
- Nidhi Mehta says
  
  December 27, 2020 at 4:56 pm
  Q3.
```
str1 = input('enter string:')
str1[::2]
```
  Reply
Rajkumar says

December 17, 2020 at 8:47 pm
Question 14: Print downward Half-Pyramid Pattern with Star (asterisk)
```
for i in range(5, 0,-1):
    print(' *' * i)
```
Reply
Noname says

November 11, 2020 at 6:55 pm
Hi! I am a beginner in Python, so thanks a lot for the exercises. I have got a question concerning exercise 3. I have written the following code:
```
 
def thatsweird(a):
    for x in a :
        if a.index(x)%2==0:
            print (x)
            
a= list(input("word: " ))
thatsweird(a)
```
It works fine as long as there are no identical letters in a row in which case it messes up. I would be very grateful if someone explained to me why or just referred me to an explanation online as I didn’t find one (yet):)

Thanks!
Reply
- Z09 says
  
  November 14, 2020 at 7:50 pm
```
string = input("Enter your word: ")
print("Original string is " + string)
print("Printing only even index chars")
for i in range(len(string)):
    even = i%2
    if even == 0:
        print("index["+ str(i) + "] " + string[i])
print("NOTE:THAT SPACE ALSO COUNTS AS A CHAR\n\tTHE COUNT STARTS FROM ZERO NOT ONE")
```
  Reply
- Priyank Palshetkar says
  
  November 24, 2020 at 4:57 pm
  Easy solution for exercise 3
```
str="pynative"
for i in range(0,len(str)-1,2):
    print(str[i])
```
  Reply
- ayush says
  
  December 14, 2020 at 10:10 am
```
name='umbrella'
for i in range(0,len(name)-1,2): 
    print(name[i])
```
  Reply
- Multicast says
  
  January 10, 2021 at 3:21 am
  Hi Noname, Whenever you try to find an index for a character Python would return the index where ever it finds it first, so if your string has an identical char Python will just give you the index for the first occurring char. hope it helps.
  
  Below is how I approached this problem:
```
def even_str(my_str):
    n = len(my_str)
    for i in range(0, n, 2):
        print(my_str[i])
even_str("pynative")
```
  Reply
suraj says

November 11, 2020 at 4:47 pm
# # Question 14: Print downward Half-Pyramid Pattern with Star (asterisk)
```
n=5
for i in range(6):
#     print(i)
    z= "* " * n
    n= n-1
    print(z)
```
Reply
Rushikesh says

November 2, 2020 at 3:07 pm
Que 5:
```
def isFirst_And_Last_Same(numberList):
    print("Given list is ", numberList)
    firstElement = numberList[0]
    lastElement = numberList[-1]
    if (firstElement == lastElement):
        return True
    else:
        return False

My_list = []
n = int(input('number of elements = '))
for i in range(0,n):
    ele = int(input(f'ele {i+1} = '))
    My_list.append(ele)
```
Reply
- Sebz says
  
  November 27, 2020 at 4:59 am
  Easy solving for Q. 5
```
list1 = [10, 20, 30, 40, 10]

bool = list1[0] == list1[-1]

print(f'The result is {bool}')
```
  Reply
Rob says

October 28, 2020 at 7:50 pm

Question 13:

Why is it print("\t\t") and not print("\n")?
I thought \t creates a tab or indent. \n drops a line doesn’t it?
Alos why \t\t and not just \t

Thanks. I enjoyed the questions finding some pretty tricky!!!

Reply
- Lokesh says
  
  November 9, 2020 at 1:52 pm
  
  \t\t means is two tab
  
  Reply
Attiya says

October 23, 2020 at 5:14 am
```
def asterisks(input):
     if input > 0:
         for y in range(input,0,-1):
              print('*'*y)
```
Reply
jamar says

October 21, 2020 at 8:28 pm
```
rows=5
for x in range(rows,0,-1):
    print('*'*x)
    print('\n')
```
Reply
- suraj says
  
  November 11, 2020 at 4:45 pm
  I have tried this way
```
n=5
for i in range(6):
#     print(i)
    z= "* " * n
    n= n-1
    print(z)
```
  Reply
Sindhu says

October 21, 2020 at 7:53 pm
For question 6,we can have like this,
```
def CompareLists(givenList):
    return (givenList[0]== givenList[len(givenList)-1]) 
list1 = [10, 20, 30, 40, 10]
list2 = [10, 20, 30, 40, 50]
print(CompareLists(list1))
print(CompareLists(list2))
```
Reply
Supriya says

October 19, 2020 at 7:56 pm
Question 15 can have a simpler solution . Which is :
```
def exponent(base, exp):
    return f'{base} raises to the power of {exp} is {base**exp}'

print(exponent(5, 4))
```
Reply
- Sindhu says
  
  October 23, 2020 at 7:54 pm
  
  Yeah!!.. That’s what am going to say!!
  
  Reply
Abdu says

October 16, 2020 at 10:26 pm
question 14
```
 for x in range(6,0,-1):
    print(x*" *")
```
Reply
Abdu says

October 16, 2020 at 10:23 pm
question 15
```
def exponent (base,exp):

    return base**exp


print(exponent(5,4))
```
Reply
Abdu says

October 16, 2020 at 9:26 am
question 11.
```
num = int(input("Enter any number: "))
reverse = 0
lst = []
while num > 0:
    reminder = num%10
    reverse = (reverse*10)+reminder
    num = num//10
    lst.append(reminder)


print(*lst,sep=" ")
```
Reply
- Abdu says
  
  October 16, 2020 at 9:28 am
```
 num = int(input("Enter any number: "))
reverse = 0
lst = []
while num > 0:
    reminder = num%10
    reverse = (reverse*10)+reminder
    num = num//10
    lst.append(reminder)


print(*lst,sep=" ")
```
  Reply
Attiya says

October 10, 2020 at 5:05 am
Simplified solution for question 14 without nested loop:
```
rows=5
for x in range(rows,0,-1):
    print('*'*x)
    print('\n')
```
Reply
Isaac says

October 9, 2020 at 1:35 am
Question 3
```
cv=0

str="pynative"
for s in str:
    if cv %2==0:
        print(s)
    cv+=1
```
Reply
Isaac says

October 9, 2020 at 1:31 am
Question 1
```
    num1=20
    num2=30
    product=num1*num2
    if product > 1000:
        print(num1 + num2)
    else:
        print(product)
```
Reply
Isaac says

October 9, 2020 at 1:25 am
Question 12
```
    def exponent(base,exp):
        return base**exp
a=exponent(2,5)
print(a)
```
Reply
Emerson says

September 22, 2020 at 12:14 pm
The question to exercise 6:
Why does a “None” appear at the end of my output?

Here is my code:
```
def onlyDivisible(numbersList):
    print("given list is", numbersList)
    print("Divisible of 5 in a list")
    for n in numbersList:
        if n % 5 == 0:
            print(n)


myList = [10, 20, 33, 46, 55]
print(onlyDivisible(myList))
```
Reply
- Sumanth says
  
  September 24, 2020 at 10:38 am
  
  Hello Emerson
  Instead of using use
  
  Reply
- Sumanth says
  
  September 24, 2020 at 10:41 am
  
  instead of using use
  
  Reply
- Sumanth says
  
  September 24, 2020 at 10:43 am
  
  Instead of using print(onlyDivisible(myList)) use onlyDivisible(myList)
  
  Reply
Sumit says

September 11, 2020 at 1:11 pm
Question 15: Write a function called exponent(base, exp) that returns an int value of base raises to the power of exp.
```
def exponential(base,exp):
    return(f"{base} raise to power {exp}: {base**exp}")

base = int(input("Enter your base integer :"))
exp = int(input("Enter your exponential integer: "))
print(exponential(base,exp))
```
Reply
Youssef Hmini says

September 7, 2020 at 2:24 am

Love it! Especially for beginners like me!

Reply

el empotrador says

September 2, 2020 at 12:08 am

jhere I share my solutions with you, hope this helps.
question 1:

print("to play this game you have to introduce two numbers.")
number1 = input("please introduce the first number: ")
number2 = input("please introduce the second number: ")
product = int(number1) * int(number2)
if product >= 1000:
    sum = int(number1) + int(number2)
    print(sum)
else:
    print(product)

question 2:

for elements in range(11):
    print("the current number is ", elements, "the previous number was: ", elements - 1 , "the sum is:  ", elements + elements - 1)

question 3:

letter = input("please introduce a word: ")
print(letter[0: len(letter):2])

question 4:

string = str(input("please introduce a word: "))
while True:
    n = input("please introduce a number shorter than the length of the shosen word: ")
    m = int(n)
    if n.isdigit() and int(n) > len(string):
        print("please introduce a shorter number than string`s length")
    elif n.isdigit() and int(n) < len(string):
        print(string[m:])
        break
print("thanks for playing")

question 5:

listOfNumbers = input("please introduce five numbers separated by space: ")
Numbers = listOfNumbers.split()#here i have leant how to accept a list as an input
if (Numbers[0] == Numbers[4]):
    print("Given the list ", Numbers)
    print("the result is True")
else:
    print("Given the list ", Numbers)
    print("the result is False")

question 6:

 def divisibility(List):
    for elements in List:
        if elements % 5 == 0:
            print(elements)
givenList = [10, 20, 33, 46, 55]
divisibility(givenList)

question 7:

string = input("please introduce a string in wich there is at least a repeated element: ")
print("the shosen string is: ", string)
elementToCount = input("please introduce the element you want to count: ")
count = string.count(elementToCount)#to count how many time a element is repeated in a string I use the .count() mehtod. the estructure of this method is: namelist.count(the element we want to count)
print(elementToCount, "appears ", count, "times in the string")

question 8:

for elements in range(1, 6):
    print(" ".join(str(elements) * elements))

question 9:

num1 = input("please introduce a number: ")
if num1 == num1[-1::-1]:
    print("the original number ", num1, "is the same as its inverse")
else:
    print("the original number is not equal to its inverse")

question 10:

list1 = [10, 20, 23, 11, 17] 
list2 = [13, 43, 24, 36, 12]
newlist1 = [ ] 
newlist2 = [ ] 
finallist = [ ]  
for elements in list1:
    if elements % 2 == 0:
        newlist1.append(elements)#in this if statement I append the odd and even elements to two different list*
for e in list2:
    if e % 2 != 0:
        newlist2.append(e)
finallist = newlist1 + newlist2 #here I add the two different lists*
print(finallist)

question 11:

 number = input("please a list of numbers separated by space: ")
givennumber = number.split()
invertednumber = givennumber[-1::-1]
separatednumber = " ".join(invertednumber)
print(separatednumber)

question 12:

 totalIncome = int(input("please introduce your total income: "))
first = int(10000) * float(0.0)#when writing floats i have to use a dot instead of a comma 
second = int(10000) * float(0.1)
remain = totalIncome - int(20000)
final = remain * float(0.2)
totalTax = first + second + final
print("$1000 * 0 % + $1000 * 0,1 % + $ ",remain, " * 0,2 = $",totalTax)

question 15:

while True:
    base = input("please introduce the base of the power: ")
    if not base.isdigit():
        print("please introduce a number")
    else:
        break
while True:
    exp = input("please introduce the exponent: ")
    if not exp.isdigit():
        print("please introduce a number")
    else:
        break
def exponent(bs,ex):
    power = int(bs)**int(ex)
    return power
print(exponent(base,exp))

bhavya says

August 27, 2020 at 11:02 pm
```
a = int(input("Input an integer : "))
n1 = int( "%s" % a )
n2 = int( "%s%s" % (a,a) )
n3 = int( "%s%s%s" % (a,a,a) )
print (n1+n2+n3)
```
I saw this somewhere… I’m stuck here.. what is this % s
In an earlier code, I saw %e and %i…
please if anyone can explain, I’d be thankful
Reply
- Rakesh Singh Choudhary says
  
  August 31, 2020 at 9:00 pm
  1 .
```
a = int(input("Input an integer: "))
```
  Input method converts the user input to a string and then returns it, hence ‘int’ is prefixed here so that we can perform addition operation at the end.
  
  2.
```
n1 = int("%s" %a)
```
  The modulo % is referred to as a “string formatting operator”, here s stands for string representation. Here n1 = 4 if a is 4. You can run type(n1) and see it is str without int being prefixed.
  3.
```
n2 = int( “%s%s” % (a,a) )
```
  Similarly, here n2 = 44 if a is 4
  4.
```
n3 = int( “%s%s%s” % (a,a,a) )
```
  Again, n3 = 444 if a is 4
  
  Hence, n1 +n2 + n3 = 492
  Also, % e and % i are exponential and integer representations respectively. You can play around by putting these in print method.
  Reply
el empotrador says

August 26, 2020 at 6:14 pm
I could not solve exercise two. However, now i found what i consider the easiest solution:
```
for elements in range(11):
    print("the current number is ", elements, "the previous number was: ", elements - 1, "the sum is: ", elements + elements - 1)
```
Reply
serpilozdemir says

August 22, 2020 at 5:34 pm
Exercises are very excited for me thx
question 15 :
```
base=6
exponent=2
print('6 raises to power of 2 is', pow(base,exponent))
```
Reply
- El empotrador says
  
  August 25, 2020 at 11:19 am
  Hello everyone,. I am new at learning python and I’ve done the first exercise in a different way. Can someone please tell me if it is correct or not??
```
 print("please introduce two numbers")
number1 = input("the first number you want to introduce is:  ")

number2 = input("the second number you want to introduce is: ")

product = int(number1) * int(number2)
if product > 1000:
	sum = int(number1) + int(number2)
	print("the sum of number1 and number2 is: ", sum)
else:
	print("the product of numer1 and number2 is: ", product) 
```
  Reply
Soumya says

August 21, 2020 at 9:39 pm
for question 15:
```
b=int(input("enter base"))
 e=int(input("enter exp"))
print(b,"raise to", e, "is",b**e)
```
Reply
DMS KARUNARATNE says

August 17, 2020 at 4:36 pm
Question No 9: another way to do it
```
def rever(num):
    #print (str(num))
    revnum=("".join(reversed(str(num))))
    #print (revnum)
    if str(num)==str(revnum):
        return True
    else:
        return False
```
Reply
- Huirong Ai says
  
  October 13, 2020 at 9:46 am
  Mine is similar:
```
  def reverseCheck(number):
    print("original number:", number)
    new_number = int(str(number)[::-1])
    print("reversed number:", new_number)
    
    if number == new_number:
        print("The original and reverse number is the same")
    else:
        print("The original and reverse number is not the same") 
```
  Reply
Dev says

August 14, 2020 at 11:49 pm
hey guys!!! Here’s a program from which u can code a calculator:
```
print("what operation do u want")
operator = input("Enter either +, -, * or /: ")

num1 = int(input("Enter first number: "))
num2 = int(input("Enter second number: "))

if operator == '+':
  print(num1, operator, num2, "=", num1+num2)
elif operator == '-':
  print(num1, operator, num2, "=", num1-num2)
elif operator == '*':
  print(num1, operator, num2, "=", num1*num2)
elif operator == '/':
  print(num1, operator, num2, "=", num1/num2) 
else:
  print("Invalid Operator")
```
Reply
- Kundan Chaudhari says
  
  August 20, 2020 at 11:10 pm
  
  what if I want more than 2 values operations
  
  Reply
Dev says

August 14, 2020 at 11:15 pm
Ques. 15:
```
def exponent(base, exp):
    result = base**exp
    print(base, "raises to the power ", exp, "is: ", result)

(exponent(5, 4))
```
Reply
- Dev says
  
  August 14, 2020 at 11:16 pm
  
  I hope this would be helpful to others!!!!
  Stay Home!!
  Stay Safe!!!!
  
  Reply
- Arkaprava Biswas says
  
  August 19, 2020 at 3:34 am
  
  best way
  
  Reply
Anusha says

August 6, 2020 at 10:53 am
question 15:
```
def exponent(base,exp):
    return base**exp
print(exponent(5,4))
```
Reply
Kristofer Kangro says

July 28, 2020 at 3:11 pm

Was its purpose to make solutions as difficult as possible simply for learning new ways of writing a simple program?
Some of the questions solutions were very challenging for me to understand as a beginner but I think it has a good and bad part to it. Bad side to it might be overcomplicating a simple question but on the other end it will teach you new ways to write a simple program.
In conclusion, questions were great and on-the-level for a beginner. Thank you!

Reply
- Vishal says
  
  July 29, 2020 at 11:13 am
  
  Thank you Kristofer for your valuable feedback.
  
  Reply
- Filippi says
  
  August 12, 2020 at 8:48 pm
  
  Your point is totally nonsense. The goal here is not to solve this problem and print an output, but study and learn python. The answares MUST be as difficult as possible, as this represents a guide were you can follow to learn a little bit, for free by the way.
  Vishal: Your job here was perfect, keep doing your best to put the most difficult answare you can get, thank you very much, best regarts
  
  Reply
Harshit Rautela says

July 26, 2020 at 1:00 pm
Q15 simple solution
```
def exponent(base, exp):
    result = base**exp
    print(result)


print(exponent(5, 4))
```
Reply
HARSH says

July 23, 2020 at 4:53 pm
```
#SHORTEST WAY OR QUESTION 9

number=input("ENTER THE NUMBER :")

if number==number[::-1]:
    print("PALINDROME")
else:
    print("NOT A PALINDROME")
```
Reply
- charlot fx says
  
  September 6, 2020 at 9:55 pm
  
  yeah i did the same way
  
  Reply
- Dushyant says
  
  October 13, 2020 at 8:36 pm
  
  This code is reversing a string and hence is inaccurate since any input taken in python without other function is always a string. You need to write different code for reversing a number which will be type integer
  
  Reply
Harshit Rautela says

July 22, 2020 at 1:18 pm
Q3 simple solution:
```
 def display_char(name):
    for i in range(0, len(name)):
        while i < len(name):
            print(name[i])
            i += 2
        break

print(display_char("pynative"))
```
Reply
- Dev says
  
  August 14, 2020 at 11:27 pm
  here’s a solutio for Ques:3:
```
list1 = ["p","y","n","a","t","i","v","e"]
list2 = list1[0:8:2]

for str in list2:
  print(str)
```
  Reply
Er. Tushar says

July 14, 2020 at 2:01 am
#Q15 Simple Solution
```
def exponent(base,exp):
    out=base**exp
    return print(out)

print("2 raise to the power 5 is:")
exponent(2,5)
print("-------------------------------------------")
print("5 raise to the power 4 is:")
exponent(5,4)
```
Reply
Nilotpal Shanu says

July 10, 2020 at 12:29 am
Q no.4
```
Str = "pynative"
host = str[4: ]
print(host)
```
Reply
- Rithesh says
  
  July 11, 2020 at 11:32 am
```
tive
```
  Reply
Aka code_teen says

July 6, 2020 at 8:20 pm
# Q2 Simple Solution :
```
prev_num = 0
for cur_num in range(10):
     print(f" current num is {cur_num} prev num is {prev_num} Sum: {cur_num+prev_num}")
     prev_num = cur_num
```
Good Luck! 😉
Reply
Alex says

July 5, 2020 at 7:18 am

My daughter studying from your tutorials; it is great!
please continue adding more exercises.

Reply
- Vishal says
  
  July 6, 2020 at 7:41 am
  
  Thank you, Alex.
  
  Reply
  - Tuur Six says
    
    July 6, 2020 at 7:47 pm
    oefening 3:
    
    Has a little mistake if you type in a word that is even you don't have the last letter: It should be: def letter(let): for index in range(0,len(let)-0,2): print("index[",index, "] " + let[index]) inputStr = "can" letter(inputStr)
    Reply
Alimul Nishat says

July 4, 2020 at 11:01 pm
Hello Vikash bro,
I am a beginner of python programming language and found this platform best for solving problems for beginners.

And i found an alternative, short and easiest way to solve the problem no 14 is :
```
for i in range(5,0,-1):
    print(i*" *")
```
Reply

Khalid says

June 30, 2020 at 9:33 pm

My solution for number 9


def reverse_check(original_num):
    """"Reverses a given number and compares it with the original"""
    original_nums = str(original_num)
    num_len = len(original_nums)
    reverse_num = ""

    for num in range(num_len):
        reverse_num += original_nums[num_len - num - 1]

    if int(original_num) == int(reverse_num):
        print(f"original number {original_num}\nThe original and reverse number are the same: True")
    else:
        print(f"original number {original_num}\nThe original and reverse number are the same: False")


reverse_check(1221)

Khalid says

June 30, 2020 at 9:31 pm

My code for number9


def reverse_check(original_num):
    """"Reverses a given number and compares it with the original"""
    original_nums = str(original_num)
    num_len = len(original_nums)
    reverse_num = ""

    for num in range(num_len):
        reverse_num += original_nums[num_len - num - 1]

    if int(original_num) == int(reverse_num):
        print(f"original number {original_num}\nThe original and reverse number are the same: True")
    else:
        print(f"original number {original_num}\nThe original and reverse number are the same: False")


reverse_check(1221)

Houari_Aouinti says

June 27, 2020 at 4:55 am

Exercice 01:


count = lambda a, b: a * b if a * b < 1000 else a + b
print(count(25, 40))

Exercice 02:


def up(pNum, cNum, i):
    for n in range(i):
        print("Current Number:", cNum, "Previous Number:", pNum, "Sum:", cNum + pNum)
        pNum, cNum = cNum, cNum + 1
up(0, 0, 10)

Exercice 03:


def pEven(string):
    for m in range(len(string)):
        if m % 2 == 0: print(f"index {m} {string[m]}")
pEven("pynative")

Exercice 04:


split = lambda string, n: string[n:]
print(split("pynative", 4))

Exercice 05:


arr = [10, 20, 30, 40, 10]
firstLast = lambda arr: True if arr[0] == arr[-1] else False
print(firstLast(arr))

Exercice 06:


array = [10, 20, 33, 46, 55]
def arrayDvd(array):
    for i in array:
        if i % 5 == 0: print(i)
arrayDvd(array)

Exercice 07:


string = "Emma is good developer. Emma is a writer"
countString = lambda string: print(f"Emma appeared {string.count('Emma')} times")
countString(string)

Exercice 08:


def pattern(n, i):
    while n > i:
        print(f"{str(i) * i}")
        i +=1
pattern(10, 1)

Exercice 09:


rev = lambda number: True if number == number[::-1] else False
print(rev(str(121)))

Exercice 10:


fList, sList, rList = [10, 20, 23, 11, 17], [13, 43, 24, 36, 12], []
def oddEve(fl, sl):
    for i, j in zip(fList, sList):
        if i % 2 != 0 or j % 2 == 0: rList.append(i); rList.append(j)
    print(rList)
oddEve(fList, sList)

karan says

August 30, 2020 at 6:45 pm

wowww………………!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

Reply

Daniel says

June 25, 2020 at 1:40 am

Hello,

I just started learning how to program. Well, just learning one program, Python. Now, I’m completely new to this stuff and I feel overwhelmed sometimes. Can anyone share some very easy easy problems that I can work on?

Thank you guys!

Reply
- Vishal says
  
  June 25, 2020 at 3:13 pm
  
  you’re welcome, Daniel
  
  Reply
Son_Volam says

June 23, 2020 at 5:44 pm
#Q9:
```
num1 = input()

if num1 == num1[-1::-1]:
    print("TRUE")
else:
    print("FALSE")
```
Reply
- HASAN says
  
  July 21, 2020 at 10:56 am
  Q(9).
```
x=input('Enter a number: ')
if x[::-1]==x:
	print(True)
else:
	print(False)
```
  Reply
- el empotrador says
  
  August 31, 2020 at 6:23 pm
  
  thanks for publishing your answer, it was very helpful for me
  
  Reply
Son_Volam says

June 23, 2020 at 5:44 pm
#Q9:
```
num1 = input()

if num1 == num1[-1::-1]:
    print("TRUE")
else:
    print("FALSE")
```
Reply
Steph says

June 17, 2020 at 7:43 pm
Regarding problem 9, is it bad practice or something to convert an int to a string to reverse it and then convert it back? This process just seems more straight forward than the answer provided.

Here is what I came up with(includes some of the answer):
```
def reverseCheck(org_number):
  test_string = str(org_number)
  reverse_str = test_string[::-1]
  if int(reverse_str) == org_number:
    print("True")
  else: 
    print("False")
  print(int(reverse_str))

print("Is the original and reverse number the same?", reverseCheck(121))
```
Reply
thet wai htut says

June 17, 2020 at 11:55 am
question 8
```
for i in range(1,6):
    for j in range(1,i+1):
        print(i,end='')
    print()
```
Reply
Dhyan says

June 13, 2020 at 4:04 pm

Hey buddy doing a wonderful job by posting such useful exercise for practice 🙂 keep it up

Reply
- Vishal says
  
  June 15, 2020 at 5:08 pm
  
  Thank you, Dhyan.
  
  Reply
Nikita says

June 9, 2020 at 8:26 pm

Please bring back the old code editor 🙁

Reply
- Vishal says
  
  June 10, 2020 at 12:21 am
  
  Hey Nikita, Please let us know if you are facing any problem. Thank you
  
  Reply
  - Dev says
    
    August 14, 2020 at 11:34 pm
    
    Sir, I only knew about the only theory about Python but when I explore on chrome for some exercises I selected this…. and this has improved my coding skills!! God Bless You
    Stay Home!!!!
    Stay Safe!!!!
    
    Reply
narender says

June 8, 2020 at 12:01 pm
Question 3:
solution :
```
s = input(‘Enter your string : ‘)
L = len(s)
print(s[0:L:2])
```
Reply
- Jon Blackwell says
  
  June 24, 2020 at 3:51 am
  
  You don’t need line 2, and variable “L” in line 3 for your solution.
  
  Reply
Ray says

June 7, 2020 at 11:20 pm

Thank you very much for the exercises. They are extremely helpful for a beginner.
Keep up the good work

Reply
- Vishal says
  
  June 8, 2020 at 9:26 am
  
  You are welcome, Ray
  
  Reply
Logan Peterson says

June 7, 2020 at 11:28 am
For the Emma question, I have a short solution that works very well.
```
a = 'Emma is a good developer. Emma is a good writer'
print(a.count('Emma'))
```
Reply
Angshumaan Basumatary says

June 6, 2020 at 5:35 pm
Question 10: Tried using user input
```
def calculate(a, h):
    k = [z for z in a if z % 2 != 0]
    b = [y for y in h if y % 2 == 0]
    c = k + b
    return c


a = int(input("Enter the size: "))
angshu = [int(x) for x in input("Enter first list").strip().split()][:a]
basu = [int(x) for x in input("Enter second list").strip().split()][:a]
i = calculate(angshu, basu)
print(i)
 
```
Reply
John says

June 3, 2020 at 4:11 pm
#Question 9 alt. solution
```
def isrev(x):
  x1 = list(str(x))
  x2 = list(str(x))
  x2.reverse()
  print(x1)
  print(x2)
  print(x1==x2)
  
isrev(121)
```
Reply
Steven-r says

May 23, 2020 at 5:29 am

Hi Vishal
As a newbie, your exercises come in really helpful and useful. Thanks so much for posting! much appreciated.

Reply
- Vishal says
  
  May 26, 2020 at 7:48 pm
  
  You are welcome, Steven-r
  
  Reply

jyotirmoy ghose says

May 23, 2020 at 12:17 am

Question 1:

def mul_or_sum(num1,num2):
   
    output= num1*num2
    if(output>1000):
        value = num1 + num2
        print("the result is : ", value)
    else:
        print("the result is : ", output)

num1= int(input("enter num1: "))
num2=  int(input("enter num2: "))
mul_or_sum(num1,num2)

Question 2:

def current_previous(number):
    for i in range(1,number):
         print("current number :", i,"previosu number: ", i-1,"sum: " ,i+ i-1)

number= int(input("enter the numebr: " ))
current_previous(number)

Question 3:

def display_even_number_string(st):
    lent=len(st)

    for i in range(0,lent,2):
        print("index[", i ,"]", st[i])


st= str(input("enter string : "))
print("original string:",st)
display_even_number_string(st)

Question 4:

def remove_string_char(st):
    
    New_st= st[number ::]
    print("remaining strings are ---> :",str(New_st))

st = str(input("enter string : ")) 
st_len=len(st)
print("length of the string is :",st_len)
number= int(input("enter the number < string len : "))
remove_string_char(st)

Question 5:

def list_check(list):
     if(list[0]==list[-1]):
         print("result is: ",bool(1))
     else:
         print("result is: ",bool(0))    

list=[]
number = int(input("enter number : "))
for i in range(number):
    value=int(input("entered number to the list : "))
    list.append(value)
    print("after adding :",list)
list_check(list)

Question 6:

list=[]
number = int(input("enter number : "))
for i in range(number):
    value=int(input("entered number to the list : "))
    list.append(value)
    print("after adding :",list)

for i in range(number):
    if(list[i]%5==0):
        print(list[i],end=" ")
    else:
        print("nothing found")

Question 7:

st=str(input("enter your string: "))
def word_count(st):
    count = dict()
    words = st.split()
    print(words)
    for i in words:
        if i in count:
            count[i] += 1
        else:
            count[i] = 1
    return count
print( word_count(st),end=" ")

Question 8: Print the following pattern

for i in range(1,6):
    for j in range(i):
        print(i,end=" ")
    print("\n")

Question 9:

number = 12
reverse=0
while(number>0):
     remainder = number%10
     print(remainder)
     reverse = (reverse*10)+remainder
    
     number=number//10
     
print(reverse)

Question 10:

list1=[10, 20, 23, 11, 17]
list2=[13, 43, 24, 36, 12]
value1= len(list1)
value2=len(list2)
new_list1=[]
new_list2=[]
final_list=[]
for i in list1:
    if(i%2!=0):
        new_list1.append(i)

for j in list2:
    if(j%2==0):
        new_list2.append(j)    

final_list=new_list1+new_list2
print(new_list1)    
print(new_list2)  
print(final_list)

jyotirmoy ghose says

May 23, 2020 at 12:16 am

list1=[10, 20, 23, 11, 17]
list2=[13, 43, 24, 36, 12]
value1= len(list1)
value2=len(list2)
new_list1=[]
new_list2=[]
final_list=[]
for i in list1:
    if(i%2!=0):
        new_list1.append(i)

for j in list2:
    if(j%2==0):
        new_list2.append(j)    

final_list=new_list1+new_list2
print(new_list1)    
print(new_list2)  
print(final_list)

Sandeep says

May 22, 2020 at 11:22 pm
Alternative way for question 1: **please excuse for any mistakes
```
 
def multiplication_or_sum(num1, num2):
    if (num1 * num2) > 1000:return('The result is %s' %(num1+num2))
    else:return('The result is %s' %(num1*num2))

num1 = int(input('enter first number:\n'))
num2 = int(input('enter second number:\n'))
print(multiplication_or_sum(num1, num2))
 
```
Reply
keshav ranjithlall says

May 7, 2020 at 10:06 pm

hey bro for solution 2: what is the + 4 in the [i : 1 + 4] for?

Reply
Mr.HAZANI says

April 20, 2020 at 7:46 pm
One point to clear:
I found that the comment section ignored the spaces that I put behind every line and changed a few marks.
Paste this modified version in your Python to get it working:
```
#Principal Variable
number = 121

#Function
def ReverseNum (num):
    snum = str(num)
    reversed = snum [::-1]
    Reversed = int(reversed)
    return Reversed
```
#Output :
```
print("original number", number)
if number == ReverseNum(number) :
    print("The original and reverse number is the same:", True)
else:
    print("The original and reverse number is the same:", False)
```
Reply
- Oury says
  
  April 27, 2020 at 12:38 pm
```
def same_backwards(num):
    '''returns true if num is the same when written backwards'''
    return str(num) == str(num)[::-1]
```
  Reply
Santosh says

April 19, 2020 at 10:29 am
Last Question :
```
list1 = [1,2,4,6,2,3]
list2 = [3,432,433,22,442]

list3 = [x for x in list1 if x % 2 != 0] + [x for x in list2 if x % 2 == 0]
print(list3)
 
```
Reply
- Vishal says
  
  April 19, 2020 at 8:31 pm
  
  Thank you, Santosh for an alternative solution
  
  Reply
  - Ankana says
    
    April 25, 2020 at 8:26 am
    list1=[10,20,40,50,70] list2=[20,60,80,90] list3=list1[1::2]+list2[1::2] print(list3)
    Reply
cyberhoax says

April 15, 2020 at 5:13 pm
A7. A very useful and short way to count the words in a string
```
a = "Emma is good developer. Emma is a writer"
c = a.count("Emma")
print(c)
```
Reply
- Vishal says
  
  April 15, 2020 at 9:22 pm
  
  Hey cyberhoax, Thank you for an alternative solution.
  
  Reply
- Nikhil K says
  
  April 27, 2020 at 10:18 pm
```
a = "Emma is good developer. Emma is a writer"
print(a.count("Emma"))
```
  Reply
- mahesh says
  
  May 11, 2020 at 7:54 pm
```
a = "Emma is good developer. Emma is a writer"
c = a.count(input('enter the word: '))
print(c)
```
  Reply
saba nadiradze says

April 3, 2020 at 12:22 am

I am learning coding for 2 weeks and it totally impoved my skills. thank you for your exercises.

Reply
- Vishal says
  
  April 3, 2020 at 8:31 pm
  
  Hey Saba, Thank you for your kind words.
  
  Reply
  - Sidra says
    
    October 1, 2020 at 5:43 pm
    
    I need the answer of two questions can I plzz help me
    
    Reply
- Nikhil muppidi says
  
  April 9, 2020 at 11:25 pm
  My code for question no 10:
```
mylist1 =  [10, 20, 23, 11, 17]
mylist2 =  [13, 43, 24, 36, 12]
oddlist = [i for i in mylist1 if i%2!=0]
evenlist = [i for i in mylist2 if i%2==0]
print(oddlist+evenlist)
```
  Reply
  - Akbar says
    
    April 18, 2020 at 7:02 am
    
    best way
    
    Reply
Anca says

April 2, 2020 at 9:40 pm

Hello! Can someone explain to me the solution for example 7?
I dont understand what this line does:
count += statement[i:i + 4] == ‘Emma’. I know about slicing but that +4 confuses me. thanx

Reply
- Vishal says
  
  April 3, 2020 at 8:44 pm
  
  Hi Anca,
  
  The statement is in the loop. Slicing starts with the start index (included) and ends at end index (excluded)
  
  For example, in the first iteration of a loop i =0
  
  Here statement[ 0 : 0 + 4] i.e., statement[0 : 4] and it will return “Emma” and if it is equal to “Emma”, then count will increment as statement become true and evaluate to value 1
  
  Reply
Florian Fasmeyer says

March 14, 2020 at 8:01 pm
Alternative solutions to pynative.com – basic exercise for beginners.
# Q1.
```
a, b = int(input('Input a')), int(input('Input b'))
prod = a*b
print(prod if prod < 1000 else a+b)
```
# Q2.
```
nums = range(10)
prev = 0
for curr in nums:
  print(prev + curr)
  prev=curr
```
# Q3.
```
usr_str = input('Feed me a string!')
print(usr_str[0::2], sep='\n')
```
# Q4.
```
str, n = 'pynative', 4
print(str[n:])
```
# Q5.
```
nums = [1, 2, 3, 4, 5, 1]
print(nums[0] == nums[-1])
```
# Q6.
```
nums = range(0, 60)
print(*[num for num in nums if num%5 == 0], sep='\n')
```
''' Take-aways

Q1 – When a condition is simple, use a ternary op.: x if (cond) else y.
Q2 – If you are using indexers, you are doing it wrong!
Q3 – Don't iterate lists, use accessors instead: [start: stop: step]
Q4 – Please, use accessors instead! ref.Q3
Q5 – DO NOT IF/ELSE a condition if you return booleans! YOU IMBECILE!
Q6 – * operator is used to unpack: a, b, c = *[1, 2, 3]. You'll love it!

Q+ – You gotta learn list comprehensions: [exp(item) for item in list].
Q+ – List comprehensions with filters: [item for item in list if cond(item)]
Reply
- Florian Fasmeyer says
  
  March 14, 2020 at 8:05 pm
  
  As I can see you did not expect me to include tags!
  Too bad, I can’t change it now. 🙂
  
  Reply
  - Vishal says
    
    March 20, 2020 at 7:03 pm
    
    Thank you, Florian Fasmeyer. Now onwards Please add your code between <pre> </pre> tag for correct indentation.
    
    Reply
- Vishal says
  
  March 20, 2020 at 6:58 pm
  
  Thank you Florian Fasmeyer for alternative solutions
  
  Reply
- newbie noob says
  
  March 26, 2020 at 3:04 pm
  
  Hey. I have no idea about any of this. But on Q1 with the answer 1000?
  
  I’m so new to all of this I didn’t quite understand why the less than symbol is being used rather than the more than symbol. Thank you in advance
  
  Reply
  - Vishal says
    
    March 26, 2020 at 7:01 pm
    
    Hi newbie, I have updated the answer. In your case, the result should be 1000.
    
    Reply
- jeena gurung says
  
  June 9, 2020 at 7:05 pm
  
  Thank you so much for the alternative solutions. Being a newbie to Python, I was struggling understand author’s solutions, you made it lot easier.
  Thank you so much again.
  
  Reply
Junaid Ali says

February 7, 2020 at 10:45 pm
My Practice :

#Question 1: Accept two int values from the user and return their product.
# If the product is greater than 1000, then return their sum
```
m=int(input("Enter Number: "))
n=int(input("Enter Number: "))
r=m*n
if r>1000:
    print(m+n)
else:
    print(r)
```
#Question 2: Given a range of numbers.
# Iterate from o^th number to the end number and print the sum of the current number and previous number.
```
n=int(input("Enter Number for fibonnica series : "))
a=0
b=1
for i in range(n):
    if i == 0:
        print("0")
    else:
        c=a+b
        a=b
        b=c
        print(c)
```
#Question 3: Accept string from the user
# and display only those characters which are present at an even index
```
str = "pynative"
for i in range(len(str)):
    if i%2==0:
        print(str[i])
```
#Question 4: Given a string and an int n,
# remove characters from a string starting from zero up to n and return a new string
```
def remove(n):
    return str[n:]

str=input("Enter string : ")
n=int(input("Enter Index : "))
print(remove(n))
```
#Question 5: Given a list of ints, return True if first and last number of a list is same
```
n=int(input("How many numbers you will enter into list : "))
A=[]
for i in range(n):
    a=int(input("Enter Number : "))
    A.append(a)

if A[0]==A[-1]:
    print("First and last number is same")
```
#Question 6: Given a list of numbers,
# Iterate it and print only those numbers which are divisible of 5
```
n=int(input("How many numbers you will enter into list : "))
A=[]
for i in range(n):
    a=int(input("Enter Number : "))
    A.append(a)

for j in A:
    if j%5==0:
        print(j,end=" ")
```
#Question 7: Return the number of times that the string appears anywhere in the given another string
```
n=input("Enter phrase that repeats the words : ")
r=input("Enter repeated word : ")
c=0
n=n.split()
for i in n:
    if i in r:
        c+=1
print(c)
```
#Question 8: Print the following pattern
```
n=int(input("Enter Number of rows :"))
for i in range(1,n+1):
    for j in range(1,n+1):
        if i>j or i==j:
            print(i,end="")
        else:
            print(end="")
    print()
```
#Question 9: Reverse a given number and return true
# if it is the same as the original number
```
n=input("ENter Number : ")
if n==n[::-1]:
    print(n)
```
#Question 10: Given a two list of ints create a third list
# such that should contain only odd numbers from the first
# list and even numbers from the second list
#Merged List is [23, 11, 17, 24, 36, 12]
```
A = [10, 20, 23, 11, 17]
B = [13, 43, 24, 36, 12]
C=[]
for i in A:
    if i%2==1:
        C.append(i)
for j in B:
    if j%2==0:
        C.append(j)
print(C)
```
Reply
- AMEENGT3 says
  
  February 27, 2020 at 10:25 pm
  
  NICE WORK
  
  Reply
- harpoon says
  
  February 28, 2020 at 9:21 am
  
  thank u this helped me a lot
  
  Reply
  - Vishal says
    
    March 26, 2020 at 7:02 pm
    
    I am glad it helped you.
    
    Reply
- AMEENGT3 says
  
  March 6, 2020 at 11:26 am
```
import turtle 
import time 
import random 
  
print ("This program draws shapes based on the number you enter in a uniform pattern.") 
num_str = input("Enter the side number of the shape you want to draw") 
turtle.speed(999)
if num_str.isdigit(): 
    squares = int(num_str) 
  
angle = 180 - 180*(squares-2)/squares 
  
turtle.up 
  
x = 0 
y = 0
turtle.setpos(x, y) 
  
  
numshapes = 9
for x in range(numshapes): 
    turtle.color(random.random(), random.random(), random.random()) 
    x += 5
    y += 5
    turtle.forward(x) 
    turtle.left(y) 
    for i in range(squares): 
        turtle.begin_fill() 
        turtle.down() 
        turtle.forward(40) 
        turtle.left(angle) 
        turtle.forward(40) 
        print (turtle.pos()) 
        turtle.up() 
        turtle.end_fill() 
  
time.sleep(11) 
turtle.bye()
```
  Reply
  - AMEENGT3 says
    
    March 6, 2020 at 11:29 am
    
    Anyone can try this
    
    Reply
- Vishal says
  
  March 9, 2020 at 6:55 pm
  
  Great Junaid Ali. Keep it up
  
  Reply

Cero says

February 7, 2020 at 4:08 pm

class Dijak:
  def_init_(self, imeInPriimek,odelek,stDosezenihTock,vrstaOcene):
    self.imeInPriimek=imeInPriimek
    self.odelek=odelek
    self.stDosezenihTock=stDosezenihTock
    self.vrstaOcene=vrstaOcene
  def vrniOceno(self):
    odstotek=self.stDosezenihTock/28*100
    if(odstotek>=88):
      return(5)
    elif(odstotek>=75):
      return(4)
    elif(odstotek>=63):
      return(3)
    elif(odstotek>=50):
      return(2)
    else:
      return(1)
  def vrniImeInPriimek(self):
    loci=self.imeInPriimek.split("")
    niz=loci[1]+","+loci[0]
    return(niz)
  def izpisObjekta(self):
    print(self.vrniImeInPriimek()+"("+self.odelek+")"+"ocena :"+str(self.vrniOceno)+","+self.vrstaOcene)
  def shraniPodatek(N):
    for i in range(N)
      objekt=Dijak(input("Dijak :")),input("Odelek :"),int(input("Tocke :")),input("Vrsta :"))
      seznam.append(objekt)
    return(seznam)
  def VrniOceneDijaka(seznamdijakov,imeInPriimek):
    for s in seznamdijakov:
      if(s.imeInPriimek==imeInPriimek):
        s.izpisObjekta()
  def povprečjeRazreda(seznamdijakov,odelek,vrstaOcene):
    vsota=0
    stevec=0
    for s in seznamdijakov:
      if(s.vrstaOcene==vrstaOcene and s.odelek==odelek):
        vsota+=s.vrniOceno()
          stevec+=1
    print(vsota/stevec)

Grant says

February 2, 2020 at 8:45 am
This is more simplistic code for #5:
```
l = []
question = str(input("Do you want to enter a number; enter yes or no: "))

while question == 'yes':
    numbers = int(input("Enter a number here: "))
    question = str(input("Do you want to continue entering numbers; enter yes or no: "))
    l.append(numbers)

if l[0] == l[-1]:
    print("The first and last numbers of", l , "are the same!")
else:
    print("The first and last numbers of", l , "are not the same!")
```
Reply
- Vishal says
  
  February 3, 2020 at 11:05 pm
  
  Grant, Thank you for your solution
  
  Reply
magesh says

January 29, 2020 at 7:20 pm
Question 9: Reverse a given number and return true if it is the same as the original number
```
print(True) if(user_input == user_input[::-1]) else print(False)
```
Reply
- Vishal says
  
  March 26, 2020 at 7:04 pm
  
  Thank you for alternative solutions
  
  Reply
magesh says

January 29, 2020 at 7:04 pm
Another easiest solution for Question 8
```
for i in range(1,6):
    print(" ".join(str(i)*i),end="\n")
```
Reply
Eric says

January 7, 2020 at 10:18 pm

Hey,

As a beginner Python programmer, these questions are extremely helpful. Even when I can’t solve them on my own and peek at the given solutions, I make sure that I 100% understand the solutions before moving on to the next question. Thanks for your hard work.

Regards,
Eric

Reply
- Vishal says
  
  January 8, 2020 at 7:34 pm
  
  Eric, Thank you for your appreciation
  
  Reply
Kirich says

November 25, 2019 at 8:02 pm
Another solution for question 7:
```
test_str = "Emma is a good developer. Emma is also a writer"
counter = test_str.count('Emma')
print("Emma appeared " + str(counter) + '  times')
```
Does it count?
Reply
- Vishal says
  
  December 4, 2019 at 3:54 pm
  
  Yes. The output is Emma appeared 2 times
  
  Reply
sreekanth says

November 4, 2019 at 6:03 pm

This is a very nice practice for the beginners who wanted to kick off their python programming .

Reply
- Vishal says
  
  November 5, 2019 at 8:56 am
  
  Sreekanth, I am glad it helped you.
  
  Reply
  - Kenneth Jay Paradiang says
    
    December 4, 2019 at 11:44 am
    
    example shows parenthesis on if statements, but pycharm pose it as a pep8 violation. is it python 2 if statement structure?
    
    Reply
    - Vishal says
      
      December 4, 2019 at 3:49 pm
      
      All codes are developed using Python 3. You can remove parentheses
      
      Reply
Dwayne Lewis says

October 5, 2019 at 10:36 am

The admin of this site is doing a really good job and am really grateful for that. Also can the admin give suggestion of how to learn programming in python because i most of the basic stuff in Python but I’m still having problem putting the syntax together.

Reply
- Vishal says
  
  October 7, 2019 at 7:23 pm
  
  Thank you, Dwayne Lewis, Answer is practice. Try to solve as many examples as you can. or try to solve StackOverflow basic questions
  
  Reply
- AKASH says
  
  October 19, 2019 at 3:45 pm
  
  all these codes are in 3.7 or 2.7 ???
  
  Reply
  - Vishal says
    
    October 20, 2019 at 11:04 pm
    
    Python 3.7
    
    Reply
DevOps in Training says

September 29, 2019 at 2:43 am
For number 10 I used a list comprehension.
```
def mergeLists(list1, list2):
    list3 = list1 + list2
    mergedList = [x for x in list3 if x%2 != 0]
    return mergedList

mergeLists(listOne, listTwo)
[23, 11, 17, 13, 43]
```
Reply
- Zlatko says
  
  November 23, 2019 at 6:57 pm
  
  yeah, but you have only odd numbers…
  
  Reply
Mc Quest says

September 11, 2019 at 11:37 pm
Another possible solution for Q 1:

# program to accept two inputs and return sum
```
firstNo = int(input("Enter first number: "))
secondNo = int(input("Enter second number: "))
print(" ")
product = (firstNo * secondNo)
print(" ")

if product > 1000:
    print("The result is ", firstNo + secondNo)
else:
    print("The result is ", product)
```
Reply
Sumit says

September 1, 2019 at 9:31 pm
# Example 3
```
def example():
    inp_str = input("Enter on string : ")
    print("Your input string is :",inp_str)
    for i in range(0, (len(inp_str)-1),2):
        print("Index ",[i],":",inp_str[i])
example()
```
Reply
Ahmad says

August 10, 2019 at 6:34 pm
i think Answer to question 3 is as simple as this:
```
word = input('Please enter a word: ')

print(word[0 : : 2])
```
Reply
- Ahmad says
  
  August 10, 2019 at 6:37 pm
  in case of Even its:
```
print(word[ 1 :  : 2])
```
  Reply
Ahmad says

August 10, 2019 at 2:06 pm
The actual answer to the Question 1 should be:
```
result = int()

while result  1000:
        print('The result is: ', first_number + second_number)
        break
```
Reply
VIgnesh says

July 17, 2019 at 3:05 pm
My answer for question number 8
```
str1 ='012345'
for i in range(len(str1)):
    print(str1[i]*i)
```
Reply
Víctor says

July 12, 2019 at 11:25 pm
Hi, there is a small mistake in the solution of question 3. Specifically the error is in line 2:
for i in range(0, len(str)-1, 2).
As it is written, the last character of a word that has an odd number of characters, for example ‘tiger’ , will never be printed out, even if this last character is present at an even idex, like in this case the letter ‘r’. This is because the built-in function range() doesn’t include the last value of the specified range. For example, list(range(0,5)) will return [0, 1, 2, 3, 4], excluding the number 5.
Therefore, the correct solution is:
```
for i in range(0, len(str), 2) #remove the -1
for i in range(0, len(str)-1, 2):
```
Reply
Barry Ford says

July 4, 2019 at 5:06 am
On Question 8, I made my solution accept user input as to the height of the pyramid. See below
```
height = int(input("Height? "))
for num in range(height):
    for j in range(num + 1):
        print(num + 1, end=" ")
    print()
```
Reply
Zhixiang says

July 3, 2019 at 11:34 pm
on exercise 1:
```
a = int(input('Please enter the first integer: '))
b = int(input('Please enter the second integer: '))

c = a * b

print ('a * b =', c)

if c > 100: 
  d = a + b
  print('sum of a and b when d >100:', a + b)
```
Reply
Chris says

June 11, 2019 at 3:19 am
Here’s a shorter solution for question 3 🙂 It uses slicing with a step of 2.
```
str = "pynative"
"".join(str[::2])
```
Output:
‘pntv’
Reply
maxime says

June 7, 2019 at 5:49 pm
There is a short way to attend question 9.
```
# Reverse a given number and return true if it is the same as the original number
original_number = input("Enter the number: ")
reverse_number = original_number[::-1]
if int(original_number) == int(reverse_number):
    print("The reversed number is the same as the original one.")
else:
    print("They are not the same.")
```
Reply
Robert Carew says

May 16, 2019 at 8:39 pm

Hello Vishal.

I really am grateful for the work you put in to make this resource. This comment is a token of my thanks. I am a beginner programmer and this is helping me increase my knowledge of Python.

Cheers.

Reply
- Vishal says
  
  May 16, 2019 at 10:14 pm
  
  Hey Robert, I am glad you liked it
  
  Reply
  - Lucky says
    
    September 5, 2019 at 5:36 pm
    
    hi Vishal , i am from south africa i also need help
    
    Reply
    - Vishal says
      
      September 5, 2019 at 9:01 pm
      
      Hi Lucky, Please tell me
      
      Reply
Bill Hardwick says

May 16, 2019 at 3:41 pm

Just a general comment on these Comment boxes. Like me, I suspect most respondents post the python code by pasting from an editor (such as the Trinket one provided here). Unfortunately the mark-up behind this Comment box does not appear to support tab characters, so the all-important pythonic indentation is lost. This could be very confusing for a beginner, particularly where multi-line code blocks are concerned. Any way you could rectify this please?

(In the meanwhile, the workaround would appear to be to manually replace any tabs with 4 spaces, but that is prone to editing error or omissions.)

Reply
- Vishal says
  
  May 16, 2019 at 10:29 pm
  
  Hey, Bill
  
  You can paste your code in pre HTML tag so it can keep indentation as it is.
  
  Reply
Bill Hardwick says

May 16, 2019 at 3:30 pm
My alternative solution to Q10:
```
list1 = [1, 2, 3, 4, 5, 6, 7, 8, 9]
list2 = [21, 22, 23, 24, 25, 26]
list1_odd = [e for e in list1 if e%2 != 0]
list2_even = [e for e in list2 if e%2 == 0]
list3 = []
list3.extend(list1_odd)
list3.extend(list2_even)
print(list1)
print(list2)
print(list3)
```
Reply
Bill Hardwick says

May 16, 2019 at 3:27 pm
May I suggest an alternative solution to Q7.
```
txt = 'Emma is a good developer. Emma is also a writer.'
count = 0
lst = txt.split()
for word in lst:
  if word == 'Emma':
    count += 1
print(f'Emma appears {count} times in the string.')
```
Reply
- Neeraj Raut says
  
  July 13, 2019 at 9:35 pm
  Just a little different and shorter approach if i may suggest…
```
def string(s):
    c=s.count("Emma")
    return f"Emma occurred {c} times"
print(string('Emma stone is great actor. Emma is genius. Emma play sports'))
```
  Reply
- Improve says
  
  May 15, 2020 at 10:11 am
  
  ? at first try I’ve solved by using this approach ?
  
  Reply
Richard says

April 23, 2019 at 9:44 pm

Hi Vishal
I think to help the beginners better, you should solve the problems without always using user defined functions, just Incase those that are not familiar with it.
Don’t mind my frequent responses, am in love with PYTHON that’s why.
Thanks

Reply
- Vishal says
  
  April 24, 2019 at 6:50 am
  
  Hey, Richard Thank You for your suggestions.
  
  Reply
Richard says

April 23, 2019 at 3:00 pm
Vishal I think your solution to question1 is a little verbose, a straight if and else statement does the job just well, it Will be much easier for beginners. I.e
```
if product>1000:
    print('sum is: ', sum)
else:
    print('product is: ', product)
```
Reply
Mdsambo says

March 30, 2019 at 7:39 pm
```
user_input = input("input any string") 
for a,  j in enumerate(range(0, len(user_input), 2)):
         print(user_name)
```
# means square bracket
Reply
- Mdsambo says
  
  March 30, 2019 at 7:42 pm
```
Print(username(j))
```
  its a square bracket
  Reply
Toby Robert says

March 14, 2019 at 12:35 pm
May I suggest a more concise solution to question no. 9?
```
orignum= 234565432
revnum=(str(orignum)[::-1])
print(revnum)
if str(orignum) == revnum:
   print('True: The number is the same when reversed')
```
Reply
- Vishal says
  
  March 14, 2019 at 12:50 pm
  
  Thank you Toby for your valuable suggestion. It will help others also.
  
  Reply
- Jasmine_a says
  
  October 24, 2020 at 6:10 pm
  hi sorry, but can you check this code, please?
  I want to write a program in which you get multi-digit numbers from the user without any restrictions on repetition and digits. It can be up to n digits and I want to add those digits in order so that I have only one digit in my output, like this example :
  input = 123874 solving = 1+2+3+8+7+4 =25 , 25 = 7 output = 7
  or , input = 14 output = 5
  
  and this is my code but it doesn’t work. can you debug this in a way that it works and be able to give any input from user?
```
def sumdigits_nonrecursive(number):
    result = number
    while result > 10:
        ac = 0         # initialize a temporary accumulator
        for c in str(result):
            # for each character of the "result" string, add to accumulator the digit value
            ac = ac + int(c)
        result = ac
    return result
```
  Reply
Joseph says

March 8, 2019 at 11:35 am
Dear Vishal,
I tried Question 1 and failed as compare to your solution. I think your question was wrongly phrased.
My solution is
#It is assumed user will enter integers only, no check on input
```
first = int(input("Enter first integer "))
second = int(input("Enter second integer "))

product = first * second
print ("Product is ", product)

if product > 1000:
    print("Sum as product > 1000 : ", first + second)
```
Your Question should have been
Question 1: Accept two integer values from user.
Calculate their product and if the product is greater than 1000
then return their sum otherwise return their product.

Regards,
Joseph
Reply
- Ahmad says
  
  August 10, 2019 at 2:02 pm
  You are right, according to the question the solution should be:
```
result = int()
while result  1000:
        print('The result is: ', first_number + second_number)
        break
```
  In this way, It will keep asking you the numbers until the product is not greater than 1000 and If the Product is greater than 1000 then it will show you the result by adding both numbers
  Reply
- Ahmad says
  
  August 10, 2019 at 2:04 pm
  sorry the actual solution: some how skipped to copy some lines
```
result = int()

while result  1000:
        print('The result is: ', first_number + second_number)
        break
```
  Reply

Python Basic Exercise for Beginners

Question 1: Given a two integer numbers return their product and if the product is greater than 1000, then return their sum

Question 2: Given a range of first 10 numbers, Iterate from start number to the end number and print the sum of the current number and previous number

Question 3: Given a string, display only those characters which are present at an even index number.

Question 4: Given a string and an integer number n, remove characters from a string starting from zero up to n and return a new string

Question 5: Given a list of numbers, return True if first and last number of a list is same

Question 6: Given a list of numbers, Iterate it and print only those numbers which are divisible of 5

Question 7: Return the total count of sub-string “Emma” appears in the given string

Question 8: Print the following pattern

Question 9: Reverse a given number and return true if it is the same as the original number

Question 10: Given a two list of numbers create a new list such that new list should contain only odd numbers from the first list and even numbers from the second list

Question 11: Write a code to extract each digit from an integer, in the reverse order

Question 12: Calculate income tax for the given income by adhering to the below rules

Question 13: Print multiplication table form 1 to 10

Question 14: Print downward Half-Pyramid Pattern with Star (asterisk)

Question 15: Write a function called `exponent(base, exp)` that returns an int value of base raises to the power of exp.

So What Do You Think?

Is this article/website helpful?

About Vishal

Python Exercises and Quizzes

Keep Reading Python

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Question 1: Given a two integer numbers return their product and if the product is greater than 1000, then return their sum

Question 2: Given a range of first 10 numbers, Iterate from start number to the end number and print the sum of the current number and previous number

Question 3: Given a string, display only those characters which are present at an even index number.

Question 4: Given a string and an integer number n, remove characters from a string starting from zero up to n and return a new string

Question 5: Given a list of numbers, return True if first and last number of a list is same

Question 6: Given a list of numbers, Iterate it and print only those numbers which are divisible of 5

Question 7: Return the total count of sub-string “Emma” appears in the given string

Question 8: Print the following pattern

Question 9: Reverse a given number and return true if it is the same as the original number

Question 10: Given a two list of numbers create a new list such that new list should contain only odd numbers from the first list and even numbers from the second list

Question 11: Write a code to extract each digit from an integer, in the reverse order

Question 12: Calculate income tax for the given income by adhering to the below rules

Question 13: Print multiplication table form 1 to 10

Question 14: Print downward Half-Pyramid Pattern with Star (asterisk)

Question 15: Write a function called exponent(base, exp) that returns an int value of base raises to the power of exp.

So What Do You Think?

Is this article/website helpful?

About Vishal

Python Exercises and Quizzes

Keep Reading Python

Leave a Reply Cancel reply

180 Comments

Comments

Leave a Reply Cancel reply

About PYnative

Python

Follow PYnative

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Question 15: Write a function called `exponent(base, exp)` that returns an int value of base raises to the power of exp.