Python List Exercise with Solutions

Last updated on July 21, 2020 | 37 Comments

A list object is mutable in Python. Python list is sequences; Each list item is assigned to its position or index. Python list is the most widely used data structure, and a good understanding of list operations is necessary. This Python list exercise aims to help developers to learn and practice list operations to improve understanding of the Python list. All questions are tested on Python 3.

Further Reading:

Explore All Python Exercises and Python Quizzes to practice Python
Also, try to solve a Python List Quiz

What included in this Python list exercise?

The exercise contains 10 questions and solutions provided for each question. This Python list coding exercise is nothing but Python List assignments to solve, where you can solve and practice different list programs, questions, problems, and challenges.

Each question includes a specific list related topic you need to practice. This list exercise covers questions on the following topics:

Python List operations and manipulations
Python List functions
Python list slicing
Python list comprehension

When you complete each question, you get more familiar with the Python list. Let us know if you have any alternative solutions. It will help other developers.

Use Online Code Editor to solve exercise questions.

Exercise Question 1: Given a Python list you should be able to display Python list in the following order

aLsit = [100, 200, 300, 400, 500]

Expected output:

[500, 400, 300, 200, 100]

Solution:

aList = [100, 200, 300, 400, 500]
aList = aList[::-1]
print(aList)

Show Solution

Hide Solution

Exercise Question 2: Concatenate two lists index-wise

list1 = ["M", "na", "i", "Ke"] 
list2 = ["y", "me", "s", "lly"]

Expected output:

['My', 'name', 'is', 'Kelly']

Solution:

We need to use list comprehension and zip() function as follows

list1 = ["M", "na", "i", "Ke"] 
list2 = ["y", "me", "s", "lly"]
list3 = [i + j for i, j in zip(list1, list2)]
print(list3)

Show Solution

Hide Solution

Exercise Question 3: Given a Python list. Turn every item of a list into its square

aList = [1, 2, 3, 4, 5, 6, 7]

Expected output:

[1, 4, 9, 16, 25, 36, 49]

Solution:

We need to use list comprehension

aList = [1, 2, 3, 4, 5, 6, 7]
aList =  [x * x for x in aList]
print(aList)

Show Solution

Hide Solution

Exercise Question 4: Concatenate two lists in the following order

list1 = ["Hello ", "take "]
list2 = ["Dear", "Sir"]

Expected output:

['Hello Dear', 'Hello Sir', 'take Dear', 'take Sir']

Solution:

list1 = ["Hello ", "take "]
list2 = ["Dear", "Sir"]

resList = [x+y for x in list1 for y in list2]
print(resList)

Show Solution

Hide Solution

Exercise Question 5: Given a two Python list. Iterate both lists simultaneously such that list1 should display item in original order and list2 in reverse order

list1 = [10, 20, 30, 40]
list2 = [100, 200, 300, 400]

Expected output:

Solution:

We need to use the zip() function here.

list1 = [10, 20, 30, 40]
list2 = [100, 200, 300, 400]

for x, y in zip(list1, list2[::-1]):
    print(x, y)

Show Solution

Hide Solution

Exercise Question 6: Remove empty strings from the list of strings

list1 = ["Mike", "", "Emma", "Kelly", "", "Brad"]

Expected output:

["Mike", "Emma", "Kelly", "Brad"]

Solution:

We can use a filter() function to remove None type from the list

list1 = ["Mike", "", "Emma", "Kelly", "", "Brad"]
resList = list(filter(None, list1))
print(resList)

Show Solution

Hide Solution

Exercise Question 7: Add item 7000 after 6000 in the following Python List

list1 = [10, 20, [300, 400, [5000, 6000], 500], 30, 40]

Expected output:

[10, 20, [300, 400, [5000, 6000, 7000], 500], 30, 40]

Solution:

Use the append() method

list1 = [10, 20, [300, 400, [5000, 6000], 500], 30, 40]
list1[2][2].append(7000)
print(list1)

Show Solution

Hide Solution

Exercise Question 8: Given a nested list extend it with adding sub list `["h", "i", "j"]` in a such a way that it will look like the following list

Given List:

list1 = ["a", "b", ["c", ["d", "e", ["f", "g"], "k"], "l"], "m", "n"]

Sub List to be added = ["h", "i", "j"]

Expected output:

['a', 'b', ['c', ['d', 'e', ['f', 'g', 'h', 'i', 'j'], 'k'], 'l'], 'm', 'n']

Solution:

list1 = ["a", "b", ["c", ["d", "e", ["f", "g"], "k"], "l"], "m", "n"]
subList = ["h", "i", "j"]

list1[2][1][2].extend(subList)
print(list1)

Show Solution

Hide Solution

Exercise Question 9: Given a Python list, find value 20 in the list, and if it is present, replace it with 200. Only update the first occurrence of a value

list1 = [5, 10, 15, 20, 25, 50, 20]

Expected output:

list1 = [5, 10, 15, 200, 25, 50, 20]

Solution:

list1 = [5, 10, 15, 20, 25, 50, 20]

index = list1.index(20)
list1[index] = 200
print(list1)

Show Solution

Hide Solution

Exercise Question 10: Given a Python list, remove all occurrence of 20 from the list

list1 = [5, 20, 15, 20, 25, 50, 20]

Expected output:

[5, 15, 25, 50]

Solution:

Use the list comprehension

list1 = [5, 20, 15, 20, 25, 50, 20]

def removeValue(sampleList, val):
   return [value for value in sampleList if value != val]
resList = removeValue(list1, 20)
print(resList)

Show Solution

Hide Solution

Comments

bhavya

August 21, 2020 at 11:01 am
Can anyone please point out the mistake, or is this code correct…..
```
list1 = [5, 10, 15, 20, 25, 50, 20]
if 20 in list1:
     list1.remove(20)
     list1.insert(3, 200)

print(list1)
```
Reply
- mohmmad
  
  September 5, 2020 at 6:09 pm
  
  you must loop over the remove function in order to work
  
  Reply
- mohmmad
  
  September 5, 2020 at 6:11 pm
```
list1 = [5, 10, 15, 20, 25, 50, 20]
for x in list1:
    if 20 in list1:
        list1.remove(20)
list1.insert(3,200)
print(list1)
```
  Reply
sheena

August 18, 2020 at 1:41 pm
```
list12 = [5, 20, 15, 20, 25, 50, 20]
for i in list12:
    if(i==20):
        list12.remove(i)
print(list12)
```
Reply
Deepak Sen

August 12, 2020 at 11:24 am

Any alternative ans for Q-2

Reply
- sheena
  
  August 18, 2020 at 1:43 pm
```
list1 = ["M", "na", "i", "Ke"]
list2 = ["y", "me", "s", "lly"]
newlist=list((zip(list1, list2)))
aa=[]
for i in newlist:
    aa.append(''.join(i))
print(aa)
```
  Reply
Naveen Kumar

July 19, 2020 at 11:11 am
question no.10
```
list1 = [5, 20, 15, 20, 25, 50, 20]
k=len(list1)
k=list1.count(20)
for i in range(k):
    list1.remove(20)
print(list1)
```
Reply
- Ravneet
  
  July 23, 2020 at 9:18 pm
  
  Thanks..it really helps:-)
  
  Reply
- nandish
  
  July 25, 2020 at 12:12 pm
```
list1 = [5, 20, 15, 20, 25, 50, 20]
list2=list(set(list1))
list2.remove(20)
print(list2)
```
  Reply
sankar nath

July 17, 2020 at 7:52 pm
Questions 4:
```
list1 = ["Hello", "Take"]
list2 = ["Dear", "sir"]

print( list1[0]+ " "+list2[0], list1[0]+ " "+ list2[1], list1[1]+" "+list2[0], list1[1]+list2[1] )
```
Reply
bharanisampath

July 16, 2020 at 12:20 pm

Any alternate answers for Q-10

Reply
- Naveen Kumar
  
  July 19, 2020 at 11:09 am
  Here is an alternate solution for question no.10
```
list1 = [5, 20, 15, 20, 25, 50, 20]
k=len(list1)
k=list1.count(20)
for i in range(k):
    list1.remove(20)
print(list1)
```
  Reply
- nandish
  
  July 25, 2020 at 12:16 pm
```
list1 = [5, 20, 15, 20, 25, 50, 20]
list2=list(set(list1))
list2.remove(20)
print(list2)
```
  Reply
Alec Nigh

June 24, 2020 at 12:08 am
Alternative answer to Q9 — Note: would have convert back to a list to satisfy the question requirements.
```
list1 = [5, 10, 15, 20, 25, 50, 20]
list1 = " ".join(map(str,list1))
list2 = list1.replace("20", "200", 1)
print(list2)
```
Reply
Qadeer Rizvi

June 23, 2020 at 3:33 am

Thanks Vishal, I am a beginner level python learner and I am doing the exercises , I found these helpful because these cover many methods of data structure and challenges as well. I enjoy solving them.

Reply
- Vishal
  
  June 25, 2020 at 3:08 pm
  
  You’re welcome, Qadeer Rizvi.
  
  Reply
Bostan Khan

June 14, 2020 at 7:38 pm

sir your article are amazing very helpful for me.keep it up and live long

Reply
- Vishal
  
  June 15, 2020 at 5:01 pm
  
  Thank you, Bostan Khan, for your kind words
  
  Reply
shubham kumar singh

June 13, 2020 at 1:07 pm

list1[2][1][2].extend(subList)
i can’t understand the indexing value.please heip me out.

Reply
- shivam pal
  
  June 17, 2020 at 11:08 am
```
list1[2][1][2].extend(["h", "i", "j"])
```
  Reply
Monika Gupta

June 11, 2020 at 11:13 am

can you explain Q4 flow of code not able to understand

Reply
- Bostan Khan
  
  June 14, 2020 at 7:33 pm
  
  its work like nested loop,which mean for each iteration of outer loop the inner loop will be executed completely.keep in mind nested loop and execute it then you guess easily
  
  Reply
Prashanth

May 29, 2020 at 8:14 pm

Good Work Vishal !! Do you run any online classes for Python. I am ready to join in your class

Reply
- Vishal
  
  May 31, 2020 at 11:13 am
  
  Hey Prashanth, I am not running any classes as of now. I will definitely let you know once I started it.
  
  Reply
Alec Nigh

May 29, 2020 at 12:02 am

Hi team,

I’m having trouble understanding the specific append questions where you have to place an item inside a specific list (Q7, Q8). Is there a trick people use to figure out how the indexing associated with the lists work? Playing around, it seems most the index changes result in an error.

Thanks!

Reply
Marcin

May 26, 2020 at 9:49 pm
Question 7
```
list1[2][2].append(7000)
```
Question 8
```
        
list1[2][1][2].extend(subList)
```
I don’t understand the index of lists. Where they come from? Does someone want to explain?
Reply
- Bostan Khan
  
  June 14, 2020 at 7:36 pm
  
  its like array indexing access ,the point here to be noted each list in the list will be consider an element of the list
  
  Reply
- Dalvir
  
  July 31, 2020 at 4:29 pm
  
  Hey Marcin
  
  Just count values in first index, then in second, until you reach the destination index to apply append/extend function.
  
  lets say in Q7.
  there are two values in first index before second index initiate so use 2 for that, then again we have 2 values in second index before 3rd and destination index start so use 2 again. Now you can use append function here which is third index.
  
  Reply
Gayathri

May 16, 2020 at 3:49 pm
for question1, can we use the below code?
```
start = 100
stop = 500
step = 100
stop += step
for i in reversed(range(start, stop, step)):
    print(i, end=" ")
```
which gives the same output as expected, maybe a lengthy code but just want to know whether we can use this method

Thanks in advance
Reply
- Ashish
  
  July 24, 2020 at 7:22 am
  
  The idea is to use the existing data and you need to supply method. If the data change, for example is has no uniform step interval, then your code fails.
  
  Reply
Shahnawaz

May 8, 2020 at 4:12 pm
question 5: i think this method is more easy and if this method is not preferred then pls reply
```
list1 = [10,20,30,40]
list2 = [100,200,300,400]
l2.reverse()

for value in range(len(l1)):
    print(list1[value],list2[value])
```
Reply
- shivam pal
  
  June 17, 2020 at 11:13 am
```
for i in list1,list2[::-1]:
  print(i)
```
  Reply
Noma

May 1, 2020 at 5:24 am

Hi, great collection of exercises. For question 7 is there any way to run a loop and extract all the elements while ignoring the sub-lists ?

Reply
- Vishal
  
  May 4, 2020 at 9:56 am
  Hey Noma, Please use the following code
```
list1 = [10, 20, [300, 400, [5000, 6000], 500], 30, 40]
for i in list1:
    if isinstance(i, list):
        continue
    else:
        print(i)
```
  Reply
- Yashu gaur
  
  August 1, 2020 at 1:33 pm
  
  Thanks sir it gave a lot of help to me. Thanks again
  
  Reply
Pallavi

April 15, 2020 at 5:38 pm

Thank you Vishal – This is by far the best website on python for practise,
request to share anylinks or references to read furtheron python topics for begineers

Reply
- Vishal
  
  April 15, 2020 at 9:25 pm
  
  Thank you, Pallavi. Within two weeks you will see new topics for beginners on PYnative
  
  Reply

Python List Exercise with Solutions

Exercise Question 1: Given a Python list you should be able to display Python list in the following order

Exercise Question 2: Concatenate two lists index-wise

Exercise Question 3: Given a Python list. Turn every item of a list into its square

Exercise Question 4: Concatenate two lists in the following order

Exercise Question 5: Given a two Python list. Iterate both lists simultaneously such that list1 should display item in original order and list2 in reverse order

Exercise Question 6: Remove empty strings from the list of strings

Exercise Question 7: Add item 7000 after 6000 in the following Python List

Exercise Question 8: Given a nested list extend it with adding sub list `["h", "i", "j"]` in a such a way that it will look like the following list

Exercise Question 9: Given a Python list, find value 20 in the list, and if it is present, replace it with 200. Only update the first occurrence of a value

Exercise Question 10: Given a Python list, remove all occurrence of 20 from the list

About Vishal

Is this article/website helpful?

Python Exercises and Quizzes

Keep Reading Python

Comments

Leave a Reply Cancel reply

Follow PYnative

Python

Join Our Newsletter

Legal Stuff

Exercise Question 1: Given a Python list you should be able to display Python list in the following order

Exercise Question 2: Concatenate two lists index-wise

Exercise Question 3: Given a Python list. Turn every item of a list into its square

Exercise Question 4: Concatenate two lists in the following order

Exercise Question 5: Given a two Python list. Iterate both lists simultaneously such that list1 should display item in original order and list2 in reverse order

Exercise Question 6: Remove empty strings from the list of strings

Exercise Question 7: Add item 7000 after 6000 in the following Python List

Exercise Question 8: Given a nested list extend it with adding sub list ["h", "i", "j"] in a such a way that it will look like the following list

Exercise Question 9: Given a Python list, find value 20 in the list, and if it is present, replace it with 200. Only update the first occurrence of a value

Exercise Question 10: Given a Python list, remove all occurrence of 20 from the list

About Vishal

Is this article/website helpful?

Python Exercises and Quizzes

Keep Reading Python

Comments

Reader Interactions

Comments

Leave a Reply Cancel reply

Footer

Follow PYnative

Python

Join Our Newsletter

Legal Stuff

Exercise Question 8: Given a nested list extend it with adding sub list `["h", "i", "j"]` in a such a way that it will look like the following list