Python Functions Exercise

Updated on: March 18, 2021 | 64 Comments

Python function is a code block or group of statements that perform a particular task. We use reuse functions whenever required.

This Python functions exercise aims to help Python developers to learn and practice how to create a function, nested functions, and use the function arguments effectively. All questions are tested on Python 3.

Also Read:

Python Functions Quiz

This exercise includes the following: –

It contains 10 questions and solutions provided for each question.
Coding exercise to solve Python function assignments, programs, questions, and challenges.

This function exercise covers questions on concepts such as function creation, function calls, function arguments, inner functions, built-in functions. Let us know if you have any alternative solutions. It will help other developers.

Use Online Code Editor to solve exercise questions.
Read Python functions to solve this exercise

Exercise 1: Create a function that can accept two arguments name and age and print its value

Show Solution

def demo(name, age):
    print(name, age)

demo("Ben", 25)

Exercise 2: Write a function `func1()` such that it can accept a variable length of argument and print all arguments value

func1(20, 40, 60)
func1(80, 100)

Expected Output:

func1(20, 40, 60)
20
40
60

func1(80, 100)
80
100

Show Solution

def func1(*args):
    for i in args:
        print(i)

func1(20, 40, 60)
func1(80, 100)

Explanation:

To accept Variable Length of Positional Arguments, i.e., To create functions that take n number of Positional arguments we use *args (prefix a parameter name with an asterisk * ).

Exercise 3: Write a function calculation() such that it can accept two variables and calculate the addition and subtraction of them. And also it must return both addition and subtraction in a single return call

Given:

def calculation(a, b):
    # Your Code

res = calculation(40, 10)
print(res)

Expected Output

50, 30

Expected Output:

Show Solution

In Python, we can return multiple values from a function. You can do this by separating return values with a comma.

def calculation(a, b):
    return a+b, a-b

res = calculation(40, 10)
print(res)

def calculation(a, b):
    return a+b, a-b

add, sub = calculation(40, 10)
print(add)
print(sub)

Exercise 4: Create a function showEmployee() in such a way that it should accept employee name, and its salary and display both. If the salary is missing in the function call assign default value 9000 to salary

Given:

showEmployee("Ben", 9000)
showEmployee("Ben")

Expected output:

Employee Ben salary is: 9000
Employee Ben salary is: 9000

Show Solution

In Python, we can specify default values for arguments when defining a function.

def showEmployee(name, salary=9000):
    print("Employee", name, "salary is:", salary)

showEmployee("Ben", 9000)
showEmployee("Ben")

Exercise 5: Create an inner function to calculate the addition in the following way

Create an outer function that will accept two parameters, a and b
Create an inner function inside an outer function that will calculate the addition of a and b
At last, an outer function will add 5 into addition and return it

Show Solution

In Python, we can create a nested function inside a function. We can use the nested function to perform complex tasks multiple times within another function or avoid loop and code duplication.

def outerFun(a, b):
    square = a**2
    def innerFun(a,b):
        return a+b
    add = innerFun(a, b)
    return add+5

result = outerFun(5, 10)
print(result)

Exercise 6: Write a recursive function to calculate the sum of numbers from 0 to 10

Expected Output:

Show Solution

def calculateSum(num):
    if num:
        return num + calculateSum(num-1)
    else:
        return 0

res = calculateSum(10)
print(res)

Exercise 7: Assign a different name to function and call it through the new name

Below is the function displayStudent(name, age). Assign a new name showStudent(name, age) to it and call through the new name

def displayStudent(name, age):
    print(name, age)

displayStudent("Emma", 26)

You should be able to call the same function using

showStudent(name, age)

Show Solution

def displayStudent(name, age):
    print(name, age)

displayStudent("Emma", 26)

showStudent = displayStudent
showStudent("Emma", 26)

Exercise 8: Generate a Python list of all the even numbers between 4 to 30

Expected Output:

[4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28]

Show Solution

print(list( range(4, 30, 2)))

Exercise 9: Return the largest item from the given list

aList = [4, 6, 8, 24, 12, 2]

Expected Output:

Show Solution

aList = [4, 6, 8, 24, 12, 2]
print(max(aList))

Comments

Hinata Uzamaki says

June 26, 2021 at 2:46 pm
Question – 5
```
def outer(a,b):
    def inner(Input):
        sum_1 = a+b
        return sum_1 
    return inner(Input)+5


n1 = int(input())
n2 = int(input())
ans = outer(n1,n2)
print(ans)
```
Reply
AndyLee says

June 22, 2021 at 5:52 am
For number three, I thought we had to remove the parenthesis for the final output, so my solution was:
```
def calculate(a,b):
    return a+b,a-b       
res = calculate(40,10)
print(*res,sep=',')
```
Reply
Arpan patidar says

May 10, 2021 at 10:20 pm

Good Content .. Very helpful for Beginner

Reply
Emmanuel Olweny says

May 7, 2021 at 3:28 pm

It is pretty good and easy to understand

Reply
priyanka sargar says

April 18, 2021 at 4:43 pm

Write a function addEvenNumber() such that it can accept a variable length of argument,

and can add all even arguments value and display

I want to know about this question can somebody will explain me how to do it??

Reply
- Pranav Bhagat says
  
  July 13, 2021 at 12:59 am
```
#i want to help 
#this is the solution ,

def addEvenNumber(*n):
    evens = []
    for j in n:
        if j%2==0:
            evens.append(j)

    a = sum(evens)
            
    Sum = 0
    for i in evens:
        Sum+=i
    return Sum,a

res1,res2 = addEvenNumber(2,89,76,55,78,4,64,7,71,26)
print(res1,res2)
```
  #if you don’t understand contact me on social media(id Pranav Bhagat)
  #i will help you understand the logic
  Reply
- Sambit S Misra says
  
  July 13, 2021 at 10:38 pm
```
list1 = []
def addEvenNumber(*args):
    for i in args:
        if i % 2 == 0:
            list1.append(i)
    return list1, sum(list1)

res1, res2 = addEvenNumber(232,24,255,196,7,77,8,90)

print(res1)
print(res2)
```
  Reply
- dara singh says
  
  July 19, 2021 at 4:01 pm
  Hello: dear
  in this solve problem:
```
List=[i*1 for i in range(2,30) if i%2==0]
print(List)
```
  are you happy?
  Reply
Dawar says

April 5, 2021 at 2:36 pm

good exercise thanks alot.It help me more. where i get little more complex question?

Reply

Renegade says

March 12, 2021 at 7:57 am

Question 4: A more comprehensive way.


def showEmployee(name, salary):
  default = 9000
  try:
    if salary == "": 
      print("Employee:", name, "Default salary is:", default)
    else:
      print("Employee:", name, "salary is:", int(salary))
  except Exception:
    print("Enter a number for salary")

giveName = input("What's your name? ")
giveSal = input("What's your salary? ")
showEmployee(giveName, giveSal)

Luis says

February 4, 2021 at 9:41 pm

Challenging exercises that sometimes force you to review the Python documentation to solve them.
I like them very much.

Reply
ItsRaaz On Youtube says

February 3, 2021 at 1:02 am

Good Exercises. Helps me a lot.

Reply
Div says

January 17, 2021 at 7:31 pm

For every solution, if you could explain the rationale behind the solution would be great. Thanks for the great work and helping the community.

Reply
Rajkumar says

December 24, 2020 at 1:48 pm
Question 8

Type 1:
```
for i in range(4,31,2):
    print(i, end=' ')
```
Type 2:
```
for i in range(4,31):
    if i%2 == 0:
        print(i, end=' ')
```
Type 3:
```
a = [4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30]
for i in a:
    if i%2==0:
        print(i, end=' ')
```
Reply
Rajkumar says

December 24, 2020 at 1:20 pm
Question 9
```
def find_largest(aList):
    
    return max(aList)

print(find_largest([4, 6, 8, 24, 12, 2]))
```
Reply
Rajkumar says

December 24, 2020 at 11:18 am
Question 6
```
def recursion (num):
    summ = 0
    for i in range(0,num):
        summ += i
        summ += 1
    print(summ)
recursion(10)
```
Reply
Rajkumar says

December 21, 2020 at 1:17 pm
Question 3.
```
def calculation(a,b):
    return a+b, a-b
print(calculation(40,10))
```
Reply
hemlata mahajan says

October 31, 2020 at 5:24 pm
```
def outer(a,b):
    def inner():
        return a+b
    return(a+b)+5

print(outer(5,6))
```
Reply
Abdu says

October 27, 2020 at 9:06 pm
question 9
```
aList = [28, 6, 8,32, 24, 12, 2]
largest = aList[0]

for x in aList:
    if x>largest:
        largest = x

print(largest)
```
Reply
Abdu says

October 27, 2020 at 9:02 pm
question 8 using for loop
```
Even_nums = []
for x in range(4,30):
    if x%2==0:
        Even_nums.append(x)
print(Even_nums)
```
Reply
Abdu says

October 23, 2020 at 11:43 pm
question 6 using for loop
```
def calculate (index):
    n=0
    for x in range (0,index+1):
        n+=x
    print(n)

calculate(10)
```
Reply
Abdu says

October 23, 2020 at 12:39 am
question 4
```
def showEmployee(name, salary=9000):

    return name,salary

print(*showEmployee("Abdu",57887)) #the asterisk will remove the parentheses  and quotation  marks
```
Reply
whelan power says

October 6, 2020 at 2:07 am
```
def outerFun(a, b):
    square = a**2
    def innerFun(a,b):
        return a+b
    add = innerFun(a, b)
    return add+5

result = outerFun(5, 10)
print(result)
```
trying to understand in the above code what square = a**2 is doing. when i ran the code without it. i still get 20. also not understanding some parts of what is going on.
Reply
- Devashish says
  
  January 2, 2021 at 7:26 pm
  
  Hi,
  You are right, square variable is of no use here.
  
  Which part you didn’t get?
  
  Reply
- AndyLee says
  
  June 22, 2021 at 9:53 am
  
  I was confused by the same thing. The instructions said nothing about squaring any numbers.
  
  Reply
ur_bantyness says

October 3, 2020 at 8:46 pm
Question no 9: list1 = [4, 6, 8, 24, 12,2]
```
max= sorted(list1)
print(max[-1])
```
Reply
mukul says

September 9, 2020 at 3:42 pm
can anyone please tell me why there is TypeError coming? thankyou
```
def func(*args):
    add = 0
    for arg in args:
        if arg > add:
            add=arg
    return add
    
aList = [4, 6, 8, 24, 12, 2]
print(func(aList))
```
Reply
- M_from_NL says
  
  September 20, 2020 at 2:04 pm
  Hi mukul,
  
  Since you’re working with *args, your for-loop will separate each given argument from the others. In this case you’re working with lists, meaning that using your for-loop with any number of lists as arguments would separate the lists. When given 1 list, a for loop on *args will unpack into an output of 1 list. Your code would execute as follows.
  
  func([4,2,6],[7,2,1]) # example using 2 lists as arguments
  for arg in args: # separates the arguments (in this case lists)
  arg = [4,2,6] # content of first item
  # if arg > add will become if [4,2,6] > 0, which will result in an error.
  
  The solution is to add another inner loop to unpack the lists, like this:
```
def func(*args):
    add = 0
    for arg in args:
        for item in arg:
          if item> add:
            add=item
    return add
    
aList = [4, 6, 8, 24, 12, 2]
print(func(aList))
```
  Reply
python says

September 3, 2020 at 3:11 pm
```
list = []
list_1 =[]
n = int(input("enter the total numbers inside list.:    "))
i = 1 
while(i <= n):
    num = int(input("enter the numbers you want to insert into list: "))
    i +=1
    list.append(num)
print(list, " <--the given list by you is here.\n ")
    
list.sort()
print(list)
print(max(list))
```
Reply
Jarin says

September 1, 2020 at 2:15 pm

I have some problem on exercise no 6 ..Can anyone help me to explain ?

Reply
KoussayDhifi says

August 30, 2020 at 3:09 am
can someone explain exersise 6 for me
```
def calculateSum(num):
    if num:
        return num + calculateSum(num-1)
    else: #why is there else here
        return 0

res = calculateSum(10)
print(res)
```
why is there else there
Reply
- M_from_NL says
  
  September 20, 2020 at 2:21 pm
  Hi Koussay,
  
  Try looking at it like this:
  The line ‘if num:’ executes the followed statement only if the num-value is still True, when num becomes 0 it would be False and go to the ‘else’-part instead.
  
  ‘return num + calculateSum(num-1)’ will return the num value to the print function but since the function is called again (with a decrementing num-value) it loops.
  
  The first round it will look like this:
```
def calculateSum(num):    # becomes calculateSum(10)
    if num: # becomes if 10: , since 10 corresponds to True, the line below will run.
        return num + calculateSum(num-1)  # return 10 + calculateSum(9) , the second part will run the code again creating a 'loop', each time decrementing the num value by one
    else: # at some point num will become 0, then the if num statement becomes False.
        return 0  # when num becomes 0 there is nothing more to add.
```
  The code does in effect the same as this one:
```
def calculateSum(num):
  result = 0
  while num != 0: 
    result = result + num
    num = num - 1
  return result

print(calculateSum(10))
```
  Reply
Anusha Muthakani says

July 30, 2020 at 8:55 pm

Hi Vishal,

Can you please explain ” Question 9: Return the largest item from the given list ” with some sorting mechanisms instead of using inbuilt fiction?

Reply
- Rohit hutagonna says
  
  August 2, 2020 at 7:13 pm
```
alist = [4, 6, 8, 24, 12, 2]

def largest_number(l):
    max_number = l[0]
    for i in range(0, len(l)):
        if max_number < l[i]:
            max_number = l[i]
    print(max_number)

largest_number(alist) #called the function
```
  Reply
Shiv Narayan sharma says

July 30, 2020 at 7:50 pm
```
#why is this code not return list of even number please reply.
list=[]
def l(a,b):
    for i in range(a,b):
        if i%2==0:
            c=list.append(i)
    return c
v=l(4,30)
print(v)
```
Reply
- Anusha Muthakani says
  
  July 30, 2020 at 8:49 pm
  Hi Shiv,
  
  The empty list should be defined inside a function and no need to assign list values to again new list. Frankly speaking, My first code is also same like as you but i separated both function call and ‘for’ loop. I got the answer, try with below code
```
def even():
    l=[]
    for i in range(4,31):
        if i%2 ==0:
            l.append(i)
    return l

print(even())
```
  Reply
- Rohit hutagonna says
  
  August 2, 2020 at 6:30 pm
```
list=[]
def l(a,b):
    for i in range(a,b):
        if i%2==0:
            list.append(i)
        c  = list
    return list
v= l(4,30)
print(v)
```
  You must assign the whole list after appending all the numbers
  I think you can’t assign and append for every number simultaneously
  Reply
- Keyur says
  
  August 8, 2020 at 5:54 pm
  
  The thing is when you use append() method on a list it doesn’t return an object, and because it doesn’t return an object you can’t assign a variable to store that object (because it doesn’t exist).
  
  So when you do, c=list.append(i) it modifies existing list and doesn’t return New list, so your variable c is basically empty.
  
  You should directly return list, instead of storing it into a variable and returning variable.
  
  Reply
  - raksha says
    
    August 16, 2020 at 12:54 am
    
    thanks
    
    Reply
- Bob Butcher says
  
  September 4, 2020 at 3:07 am
  
  print(list) insted of print(v) in the last line of code. Also return in the line 6 is not needed.
  
  Reply
Hassan Turi says

July 12, 2020 at 2:16 pm

I have only one suggestion as I am a new programmer so please don’t provide solutions with built-in functions use full code without built-in in solutions

Reply
Vell says

July 2, 2020 at 9:51 am
Good day sir,
For Q6, this was your answer, can you explain on what is going on with the conditional statements in depth? I have trouble understanding them,Thanks!
```
def calculateSum(num):
    if num:
        return num + calculateSum(num-1)
    else:
        return 0

res = calculateSum(10)
print(res)
```
Reply
- Hellboy says
  
  September 23, 2020 at 6:23 pm
  
  It is a “recursion” taking place in the above program and in the “if” statement when “num” value becomes zero the condition would not stand true. Here’s how it works
  num = 10
  (this is the result that gets stored to be returned) = 10 + calculatesum(9)
  
  then the function repeats again
  (result stored) = 10+9+calculatesum(8)
  same step repeats up to 1
  (result stored)= 10+9+8+7+6+5+4+3+2+1+calculatesum(0) –>in this last recursion the function returns “0” thus the sum would become
  10+9+8+7+6+5+4+3+2+1+0 = 55
  and the return function returns the sum.
  
  Reply
Shahnawaz khan says

June 2, 2020 at 3:24 pm
```
def outerFun(a, b):
    square = a**2        // why this line please tell me
    def innerFun(a,b):
        return a+b
    add = innerFun(a, b)
    return add+5

result = outerFun(5, 10)
print(result)
```
Reply
- Vishal Sharma says
  
  June 21, 2020 at 11:27 pm
  
  If u not understand this line u can use pass instead of this linee
  
  Reply
- Anukriti says
  
  July 24, 2020 at 3:17 am
  
  yeah I have same doubt
  
  Reply
- beraat says
  
  July 27, 2020 at 9:11 pm
  
  yes, really why?
  
  Reply
Alec Nigh says

May 14, 2020 at 10:28 pm
Hi Vishal! Big fan of your webpages. So I’m having trouble with Q 8… I want to create a class and then solve the problem and this is what I wrote:
```
def PythonList(x):
  for x in range(4,30):
    if x % 2 == 0:
      print(x)
    else:
      break
print(PythonList(x))
```
```
can you let me know how you would approach this? Thank you!
```
Reply
- Vishal says
  
  May 17, 2020 at 8:15 pm
  hey Alec Nigh,
  
  You should use built-in function if available instead of creating custom logic. Still, if you want to solve it using custom function then you can refer to the following
```
numList = []


def PythonList(start, end):
    for x in range(start, end):
        if x % 2 == 0:
            numList.append(x)
    return numList


print PythonList(4, 30)
```
  Reply
  - Alec Nigh says
    
    July 9, 2020 at 10:14 am
    
    Thanks Vishal! I see I wasn’t using variables correctly in my original program.
    
    Reply
  - Dev says
    
    August 17, 2020 at 11:53 pm
    the shortest solution I got for ques. 8:
    
    list = [] for i in range(4,30,2): list.append(i) print(list)
    Reply
- manuel says
  
  June 3, 2020 at 12:53 am
  Hi Alec,
  That’s my approach, didn’t like theirs (although, time-wise, much better).
```
x = range(4, 30)

for line in x:
    if line % 2 == 0:
        print(line)
```
  Reply
sahil sachdeva says

May 10, 2020 at 1:06 am

Hello sir. I just wanted to ask that in question 4 cant we use define function using two arguments and then use if write the function ? can you tell me if this is possible ? if yes how we will write the main code.

Reply
Aashish says

May 5, 2020 at 11:44 pm
Hello sir. Please let me help to understand this I am not able to understand this. the question and the logic as well.

Exercise Question 2: Write a function func1() such that it can accept a variable length of argument and print all arguments value
```
def func1(*args):
    for i in args:
        print(i)

func1(20, 40, 60)
func1(80, 100)
```
Reply
- Vishal says
  
  May 7, 2020 at 8:33 pm
  
  Hey, Ashish, we Use *args to get the variable number of positional arguments. if you defined function like def func1(*args) you can now pass n number of postional arguments.
  
  Reply
Nikhil K says

April 28, 2020 at 3:12 pm
Q9:
```
aList = [4, 6, 8, 24, 12, 2]
print(sorted(aList)[-1])
```
Reply
- Vamshi says
  
  May 26, 2020 at 6:55 pm
```
aList = [4, 6, 8, 24, 12, 2]
aList.sort(reverse=True)
print(aList.pop(0))
```
  Reply
- Silent fighter says
  
  July 8, 2021 at 4:46 pm
  
  It’s mean that first of all that we use sorted () because for this all elements become in ascending order [2,4,6,8,12,24] than and here [-1] mean to show last digit 24…….for example [-2] it showing 2nd last digit which is in list 12
  
  Reply
Nikhil K says

April 28, 2020 at 3:01 pm
Q6:
```
def cal(n):
    sum=0
    for i in range(1, n, 1):
        sum = sum +i
    print(sum)
rev = cal(11)
```
Reply
Anna says

April 22, 2020 at 12:37 am

Hello,
There is a mistake in the description of exercise # 8.
The range should be between 4 to 30 (not 4 to 40) in order to see the list of even number [4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28]

Reply
- Vishal says
  
  April 22, 2020 at 10:40 am
  
  Thank you, Anna, for your observation. I have updated the example you mentioned.
  
  Reply
  - Dev says
    
    August 17, 2020 at 11:58 pm
    
    I did it sir!!!!!Due to your efforts….
    I have no words to complement you!!
    You are doing a great job.
    
    Reply
    - Vishal says
      
      August 19, 2020 at 11:42 am
      
      Thanks for the appreciation dev.
      
      Reply
      - dara singh says
        
        July 19, 2021 at 3:48 pm
        
        for i in range(30): if i%2==0: print("in This 2 to 28",i) #another conticen method num=list(range(4,30,4)) print(num)

Python Functions Exercise

Exercise 1: Create a function that can accept two arguments name and age and print its value

Exercise 2: Write a function `func1()` such that it can accept a variable length of argument and print all arguments value

Exercise 3: Write a function calculation() such that it can accept two variables and calculate the addition and subtraction of them. And also it must return both addition and subtraction in a single return call

Exercise 4: Create a function showEmployee() in such a way that it should accept employee name, and its salary and display both. If the salary is missing in the function call assign default value 9000 to salary

Exercise 5: Create an inner function to calculate the addition in the following way

Exercise 6: Write a recursive function to calculate the sum of numbers from 0 to 10

Exercise 7: Assign a different name to function and call it through the new name

Exercise 8: Generate a Python list of all the even numbers between 4 to 30

Exercise 9: Return the largest item from the given list

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Exercise 1: Create a function that can accept two arguments name and age and print its value

Exercise 2: Write a function func1() such that it can accept a variable length of argument and print all arguments value

Exercise 3: Write a function calculation() such that it can accept two variables and calculate the addition and subtraction of them. And also it must return both addition and subtraction in a single return call

Exercise 4: Create a function showEmployee() in such a way that it should accept employee name, and its salary and display both. If the salary is missing in the function call assign default value 9000 to salary

Exercise 5: Create an inner function to calculate the addition in the following way

Exercise 6: Write a recursive function to calculate the sum of numbers from 0 to 10

Exercise 7: Assign a different name to function and call it through the new name

Exercise 8: Generate a Python list of all the even numbers between 4 to 30

Exercise 9: Return the largest item from the given list

About Vishal

Related Tutorial Topics:

Python Exercises and Quizzes

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Exercise 2: Write a function `func1()` such that it can accept a variable length of argument and print all arguments value